Here's how to write your code so that it works, (basically your design
has static in the wrong place)
class G4PreCompoundModel
{
public:
static G4PreCompoundModel& GetCreatorModels()
{
static G4PreCompoundModel theModel;
return theModel;
}
private:
G4PreCompoundModel()
{
uno = 1;
dos = 2;
theCreatorModels.push_back(&uno);
theCreatorModels.push_back(&dos);
}
int uno;
int dos;
vector<int*> theCreatorModels;
};
Now all you have to do is add whatever methods you require to
G4PreCompoundModel.
john
Thanks, John for your assistance. A sent a reply yesterday, but it
does not appear published. Therefore, I write it again (sorry in
advance if it shows up duplicated).Well, when I received your
suggestion I had already more or less "elegantly" (or efficiently)
solved the problem. Here you have the code:
///begin of the code
// about static vector (of pointers) member function
//19/05/07...my solution
#include <iostream>
#include <vector>
using namespace std;
class G4PreCompoundModel
{
public:
static int uno, dos;
static vector<int*> * GetCreatorModels()
{ return &
G4PreCompoundModel::theCreatorModels; }
// private:
static vector<int*> theCreatorModels;
private:
static bool __init;
static bool init() {
theCreatorModels.push_back(&uno);
theCreatorModels.push_back(&dos);
return true;
}
};
int G4PreCompoundModel::uno=1;
int G4PreCompoundModel::dos=2;
vector<int*> G4PreCompoundModel::theCreatorModels;
bool G4PreCompoundModel::__init = G4PreCompoundModel::init();
int main ()
{
int uno=1,dos=2;
vector<int*> * p=G4PreCompoundModel::GetCreatorModels();
cout<<"The returned pointer 'p' (to vector of pointers to integers)=
"<<p<<endl;
int ** p1;
int ** p2;
p1=&((*p).at(0))+1;
p2=&((*p).at(1));
if(uno==*((*p).at(0)) && dos==*((*p).at(1)))
cout<<"Ok...uno =*((*p).at(0)) = "<<*((*p).at(0))<<" and dos =
*((*p).at(1)) ="<<*((*p).at(1))<<endl;
if (p1==p2)
{cout<<"Right!..the pointers (to vector member pointers to integers)
are sequential!!"<<endl;
cout<<"&((*p).at(0))+1="<<&((*p).at(0))+1<<"
&((*p).at(1))="<<p2<<endl;}
cout<<"The vector member pointers (to integers..) are not sequential
(why shoud they?):"<<endl;
cout<<"(*p).at(0) = "<<(*p).at(0)<<" (*p).at(1) =
"<<(*p).at(1)<<endl;
return 0;
}
////// end of the code
When implementing your suggestion I had to comment the /private
declaration in G4PreCompoundModel class in order to have acces to its
constructor and hence to ints vector members. Here you hacve it:
///begin of the code
// about static vector (of pointers) member function
//20/05/07...John Allison's solution
#include <iostream>
#include <vector>
using namespace std;
class G4PreCompoundModel
{
public:
static G4PreCompoundModel& GetCreatorModels()
{
static G4PreCompoundModel theModel;
return theModel;
}
// private:
G4PreCompoundModel()
{
uno = 1;
dos = 2;
theCreatorModels.push_back(&uno);
theCreatorModels.push_back(&dos);
}
int uno;
int dos;
vector<int*> theCreatorModels;
};
int main ()
{
int uno=1,dos=2;
int * puno;
int * pdos;
puno =G4PreCompoundModel::GetCreatorModels().theCreatorModels.at(0);
pdos =G4PreCompoundModel::GetCreatorModels().theCreatorModels.at(1);
if(uno==*puno && dos==*pdos)
cout<<"Ok...uno =*puno = "<<*puno<<" and dos = *pdos
="<<*pdos<<endl;
if (&puno+1==&pdos) {
cout<<"The pointers (to vector member pointers to integers) are
sequential:"<<endl;
cout<<"&puno+1="<<&puno+1<<" &pdos="<<&pdos<<endl;
cout<< "why they are not????"<<endl;}
else
{ cout<<" The pointers (to vector member pointers to integers) are
NOT sequential:"<<endl;
cout<<"&puno+1="<<&puno+1<<" &pdos="<<&pdos<<endl;
cout<< "why ????"<<endl;}
cout<<"The vector member pointers (to integers..) are not sequential
(why shoud they?):"<<endl;
cout<<"puno = "<<puno<<" pdos = "<<pdos<<endl;
return 0;
}
///end of the code
But which puzzles me is the fact that the pointers to the vector
members (also pointers to integers, by he way) are not
sequential...and they are sequential when constructucted in "my
way" (my code). Can you tell me why?? Cheers and many thanks in
advance
Jose Manuel
Jose Manuel
