P
Paolo Elvati
Hi,
I noticed a "strange" behavior of argparse.
When running a simple code like the following:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument(
"-o",
default = 'fake',
dest = 'OutputFile',
type = argparse.FileType('w')
)
args = parser.parse_args()
I noticed that the default file (fake) is created every time I run the
code, even when I explicitly set the -o flag, in which case it will
produce both files.
My goal instead is to erite the default file ONLY if the flag is not specified.
For the moment, I solved it simply by removing the "default=fake" and
adding the "required=True" keyword, but I was wondering what is the
correct way of doing it (or if it is simply a bug).
Thank you,
Paolo
I noticed a "strange" behavior of argparse.
When running a simple code like the following:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument(
"-o",
default = 'fake',
dest = 'OutputFile',
type = argparse.FileType('w')
)
args = parser.parse_args()
I noticed that the default file (fake) is created every time I run the
code, even when I explicitly set the -o flag, in which case it will
produce both files.
My goal instead is to erite the default file ONLY if the flag is not specified.
For the moment, I solved it simply by removing the "default=fake" and
adding the "required=True" keyword, but I was wondering what is the
correct way of doing it (or if it is simply a bug).
Thank you,
Paolo