argv[0] and __file__ inconsistency

[Hai Vu]

I currently use ActivePython 2.5.1. Consider the following code which
I saved as cmdline.py:
import sys
print sys.argv[0]
If I invoke this code as 'python cmdline.py', then the output is:
cmdline.py
If I invoke it as 'cmdline.py', then the output is:
C:\Users\hai\src\python\cmdline.py

The same happens for __file__. My question: do you have any
suggestions for a more consistent way to figure out the full path of
your script?

 

[John Machin]

I currently use ActivePython 2.5.1. Consider the following code which
I saved as cmdline.py:
import sys
print sys.argv[0]
If I invoke this code as 'python cmdline.py', then the output is:
cmdline.py
If I invoke it as 'cmdline.py', then the output is:
C:\Users\hai\src\python\cmdline.py

The same happens for __file__. My question: do you have any
suggestions for a more consistent way to figure out the full path of
your script?

use os.path.abspath

 

[Benjamin M. A'Lee]

I currently use ActivePython 2.5.1. Consider the following code which
I saved as cmdline.py:
import sys
print sys.argv[0]
If I invoke this code as 'python cmdline.py', then the output is:
cmdline.py
If I invoke it as 'cmdline.py', then the output is:
C:\Users\hai\src\python\cmdline.py

The same happens for __file__. My question: do you have any
suggestions for a more consistent way to figure out the full path of
your script?

How about::

from os.path import abspath
scriptname = abspath(sys.argv[0])

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iD8DBQFHeXXuEUZDNrttL6ARAh+6AKDIuqZr76t94DnRWtULHXmZEY7oNgCgklEr
Nnzko5YaVkEa7Tlanz/0Ehk=
=b4SC
-----END PGP SIGNATURE-----

 

[Hai Vu]

use os.path.abspath

Bingo! This is just what the doctor ordered. Thank you.
Hai