C
Chris Hare
I have a database query result (see code below). In PHP, I would have said
list(var1,var2,var) = $result
and each element in the list would be assigned to each of the named variables. I have my data coming out of the database, and I can see it is a list. so my question is, instead of having to do the variable assignment as I have it here, is there a way more like PHP or am I stuck with it?
import sqlite3 as sqlite
try:
print "connecting to disk db ..."
conn = sqlite.connect("netcomm.db")
except:
print "oops"
print "retrieving data"
cursor = conn.cursor()
cursor.execute('select * from net where NetNumber > 0')
list = cursor.fetchone()
print list
print len(list)
for item in list:
print item
netNumber = list[0]
netType = list[1]
netConditions = list[2]
netStartLocal = list[3]
NCS = list[4]
NCS1 = list[5]
RADAR = list[6]
NetFreq = list[7]
Repeater = list[8]
Notes = list[9]
list(var1,var2,var) = $result
and each element in the list would be assigned to each of the named variables. I have my data coming out of the database, and I can see it is a list. so my question is, instead of having to do the variable assignment as I have it here, is there a way more like PHP or am I stuck with it?
import sqlite3 as sqlite
try:
print "connecting to disk db ..."
conn = sqlite.connect("netcomm.db")
except:
print "oops"
print "retrieving data"
cursor = conn.cursor()
cursor.execute('select * from net where NetNumber > 0')
list = cursor.fetchone()
print list
print len(list)
for item in list:
print item
netNumber = list[0]
netType = list[1]
netConditions = list[2]
netStartLocal = list[3]
NCS = list[4]
NCS1 = list[5]
RADAR = list[6]
NetFreq = list[7]
Repeater = list[8]
Notes = list[9]