cannot get html content of tag with BeautifulSoup

S

someone

Hello,

does anyone know how to get html contents of an tag with
BeautifulSoup? In example I'd like to get all html which is in first
<p> tag, i.e. <span id="foo">This is paragraph</span> <b>one</b>. as
unicode object

p.contents gives me a list which I cannot join TypeError: sequence
item 0: expected string, Tag found

Thanks!


from BeautifulSoup import BeautifulSoup
import re

doc = ['<html><head><title>Page title</title></head>',
'<body><p id="firstpara" align="center"><span id="foo">This is
paragraph</span> <b>one</b>.</p>',
'<p id="secondpara" align="blah">This is paragraph <b>two</b>.</
p>',
'</body></html>']
soup = BeautifulSoup(''.join(doc))
#print soup.prettify()
r = re.compile(r'<[^<]*?/?>')
for i, p in enumerate(soup.findAll('p')):
#print type(p) #<class 'BeautifulSoup.Tag'>
#print type(p.contents) #list
content = "".join(p.contents) #fails

p_without_html = r.sub(' ', content)
print p_without_html
 
S

someone

Hello,

does anyone know how to get html contents of an tag with
BeautifulSoup? In example I'd like to get all html which is in first
<p> tag, i.e. <span id="foo">This is paragraph</span> <b>one</b>. as
unicode object

p.contents gives me a list which I cannot join TypeError: sequence
item 0: expected string, Tag found

Thanks!

from BeautifulSoup import BeautifulSoup
import re

doc = ['<html><head><title>Page title</title></head>',
       '<body><p id="firstpara" align="center"><span id="foo">This is
paragraph</span> <b>one</b>.</p>',
       '<p id="secondpara" align="blah">This is paragraph <b>two</b>.</
p>',
       '</body></html>']
soup = BeautifulSoup(''.join(doc))
#print soup.prettify()
r = re.compile(r'<[^<]*?/?>')
for i, p in enumerate(soup.findAll('p')):
    #print type(p) #<class 'BeautifulSoup.Tag'>
    #print type(p.contents) #list
    content = "".join(p.contents) #fails

    p_without_html = r.sub(' ', content)
    print p_without_html

p.renderContents() was what I've looked for
 

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