Can't define template member function using VC++ 6.0.

[Jason Heyes]

How can I define the member function of this template class using VC++ 6.0?
The only way I got it to work was to define the member function inline.

template <typename T>
class Seq
{
public:
template <typename Pred>
Seq<T> find(Pred pred) const;
};

Any help is appreciated.

 

[ES Kim]

How can I define the member function of this template class using VC++ 6.0?
The only way I got it to work was to define the member function inline.

template <typename T>
class Seq
{
public:
template <typename Pred>
Seq<T> find(Pred pred) const;
};

Defining a template member function is something like this:

template<typename T>
template <typename Pred>
Seq<T> Seq<T>::find(Pred pred) const { /* ... */ }

But if VC++ complains about this, you have no choice other than making
it inline. Don't worry about code bloat -- if the function is complex enough,
it will not be inlined anyway. ;-)

 

[Jason Heyes]

Defining a template member function is something like this:

template<typename T>
template <typename Pred>
Seq<T> Seq<T>::find(Pred pred) const { /* ... */ }

But if VC++ complains about this, you have no choice other than making
it inline. Don't worry about code bloat -- if the function is complex
enough,
it will not be inlined anyway. ;-)

Ok thanks for the help.

 

[Jonathan Turkanis]

VC++ didn't support out-of-class definitions of member templates until 7.1.

If this is a concern, you can use the microsoft pragma auto_inline to disable
inline expansion.

Jonathan