clarificaiton with pointers

[satya123]

Hi all,

I was wondering whether the following code is proper i want to modify the values of a and b

#include <stdio.h>

void modify(int &, int &);

int main(int argc, char *argv[])
{
int a=12;
int b=13;

modify(&a, &b);
}

void modify(int &p, int &q)
{
int *f1, *f2;
f1=p;
f2=q;
*f1 = 21;
*f2 = 31;
printf("%d%d",*f1,*f2);
}

Is it possible to pass the address parameters like the one i have shown? i know it is mistake and we need to give pointers to actually make it work? but why the above code does not work?

thanks in advance,

regards,
satya