command line log file parsing

[Euan]

Hi,
Please advise best cmd line method to parse a log file to return lines that meet certain criteria. For example:
Input (log file)
2004.01.26 11:21:20.461 874 /servlet/user
2004.01.26 11:23:30.211 64 /servlet/user2
Perl command
(print top STDOUT all lines where the third column > 500)
Output

2004.01.26 11:21:20.461 874 /servlet/user

Thanks.......

 

[Anno Siegel]

Hi,
Please advise best cmd line method to parse a log file to return lines
that meet certain criteria. For example:
Input (log file)
2004.01.26 11:21:20.461 874 /servlet/user
2004.01.26 11:23:30.211 64 /servlet/user2
Perl command
(print top STDOUT all lines where the third column > 500)
Output

Check out the -a switch to perl (perldoc perlrun) and the @F array
(perldoc perlvar).

Anno

 

[John W. Krahn]

Please advise best cmd line method to parse a log file to return lines
that meet certain criteria. For example:
Input (log file)
2004.01.26 11:21:20.461 874 /servlet/user
2004.01.26 11:23:30.211 64 /servlet/user2
Perl command
(print top STDOUT all lines where the third column > 500)
Output

perl -nae'print if $F[2] > 500' log_file


John