Confused by compiler warning

  • Thread starter James H. Newman
  • Start date
J

James H. Newman

I am playing with some code that has been automatically generated
from ASN.1 data specification found in RFC 3280. One of the structures
generated reads as follows:

typedef struct TBSCertList {
Version_t *version /* OPTIONAL */;
AlgorithmIdentifier_t signature;
Name_t issuer;
Time_t thisUpdate;
struct Time *nextUpdate /* OPTIONAL */;
struct revokedCertificates {
A_SEQUENCE_OF(struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions *crlEntryExtensions /
* OPTIONAL */;

/* Context for parsing across buffer boundaries */
asn_struct_ctx_t _asn_ctx;
} ) list;

/* Context for parsing across buffer boundaries */
asn_struct_ctx_t _asn_ctx;
} *revokedCertificates;
struct Extensions *crlExtensions /* OPTIONAL */;

/* Context for parsing across buffer boundaries */
asn_struct_ctx_t _asn_ctx;
} TBSCertList_t;

/* Implementation */
extern asn_TYPE_descriptor_t asn_DEF_TBSCertList;
}

where A_SEQUENCE_OF() is defined as

#define A_SEQUENCE_OF(type) \
struct { \
type **array; \
int count; /* Meaningful size */ \
int size; /* Allocated size */ \
void (*free)(type *); \
}

The preprocessor expands this as

typedef struct TBSCertList {
Version_t *version;
AlgorithmIdentifier_t signature;
Name_t issuer;
Time_t thisUpdate;
struct Time *nextUpdate;
struct revokedCertificates {
struct {
struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions *crlEntryExtensions;
asn_struct_ctx_t _asn_ctx;
} **array;
int count;
int size;
void (*free) (struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions * crlEntryExtensions;
asn_struct_ctx_t _asn_ctx;
} *);
} list;

asn_struct_ctx_t _asn_ctx;
} *revokedCertificates;
struct Extensions *crlExtensions;

asn_struct_ctx_t _asn_ctx;
} TBSCertList_t;

This compiles all right, but the GCC compiler generates the
following warning:

TBSCertList.h:47: warning: structure defined inside parms
TBSCertList.h:47: warning: `struct Member' declared inside parameter list
TBSCertList.h:47: warning: its scope is only this definition or
declaration, which is probably not what you want

Line 47 is the line that reads

} ) list;

in the code above, before the preprocessing.

Now I want to believe that this code is generated the way it is
generated for some good reason. What I do not understand is what the
compiler is complaining about. Anybody care to explain? What is it about
struct Member that the compiler reckons that that's not what we want?
 
P

Peter Nilsson

James H. Newman said:
        This compiles all right, but the GCC compiler
generates the following warning:

TBSCertList.h:47: warning: structure defined inside parms
TBSCertList.h:47: warning: `struct Member' declared inside parameter list
TBSCertList.h:47: warning: its scope is only this definition or
declaration, which is probably not what you want

This is Question 11.5 in the FAQ...

http://c-faq.com/ansi/structinproto.html
 
J

Jack Klein

I am playing with some code that has been automatically generated
from ASN.1 data specification found in RFC 3280. One of the structures
generated reads as follows:

typedef struct TBSCertList {
Version_t *version /* OPTIONAL */;
AlgorithmIdentifier_t signature;
Name_t issuer;
Time_t thisUpdate;
struct Time *nextUpdate /* OPTIONAL */;
struct revokedCertificates {
A_SEQUENCE_OF(struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions *crlEntryExtensions /
* OPTIONAL */;

/* Context for parsing across buffer boundaries */
asn_struct_ctx_t _asn_ctx;
} ) list;

/* Context for parsing across buffer boundaries */
asn_struct_ctx_t _asn_ctx;
} *revokedCertificates;
struct Extensions *crlExtensions /* OPTIONAL */;

/* Context for parsing across buffer boundaries */
asn_struct_ctx_t _asn_ctx;
} TBSCertList_t;

/* Implementation */
extern asn_TYPE_descriptor_t asn_DEF_TBSCertList;
}

where A_SEQUENCE_OF() is defined as

#define A_SEQUENCE_OF(type) \
struct { \
type **array; \
int count; /* Meaningful size */ \
int size; /* Allocated size */ \
void (*free)(type *); \
}

The preprocessor expands this as

typedef struct TBSCertList {
Version_t *version;
AlgorithmIdentifier_t signature;
Name_t issuer;
Time_t thisUpdate;
struct Time *nextUpdate;
struct revokedCertificates {
struct {
struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions *crlEntryExtensions;
asn_struct_ctx_t _asn_ctx;
} **array;
int count;
int size;
void (*free) (struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions * crlEntryExtensions;
asn_struct_ctx_t _asn_ctx;
} *);
} list;

asn_struct_ctx_t _asn_ctx;
} *revokedCertificates;
struct Extensions *crlExtensions;

asn_struct_ctx_t _asn_ctx;
} TBSCertList_t;

This compiles all right, but the GCC compiler generates the
following warning:

TBSCertList.h:47: warning: structure defined inside parms
TBSCertList.h:47: warning: `struct Member' declared inside parameter list
TBSCertList.h:47: warning: its scope is only this definition or
declaration, which is probably not what you want

Line 47 is the line that reads

} ) list;

in the code above, before the preprocessing.

Now I want to believe that this code is generated the way it is
generated for some good reason. What I do not understand is what the
compiler is complaining about. Anybody care to explain? What is it about
struct Member that the compiler reckons that that's not what we want?

C has something called "prototype scope". It applies to both names
and types that are defined inside the argument list of a function
prototype. These definitions go out of scope at the end of the
prototype.

You can see this most easily in names:

int func(int argument);
int func(int different);
int func(int x)
{
return x + 1;
}

The compiler will not complain that because the first prototype names
the argument "argument" but the second prototype for the same function
names it "different". Nor that the function definition gives it yet a
third name.

The same thing applies to types such as structs, unions, and enums
defined in a prototype scope. Consider this:

int func( struct two_ints { int x; int y; } );

struct two_ints file_scope_two_ints my_two_ints;

Compiling a file containing these two lines will is required to
generate a diagnostic on the struct object definition, because there
is no definition of "struct two_ints" in scope at that point.

In fact, if we insert a third line between the two, to get:

int func( struct two_ints { int x; int y; } );
struct two_ints { double a; double b; double c; };
struct two_ints file_scope_two_ints my_two_ints;

Then the object "my_two_ints" will actually contain three doubles, and
a later call in the same translation unit:

int result = func( my_two_ints );

....will net a diagnostic about calling "func" with an incompatible
argument type.

That is why struct, union, and enum definitions are usually defined
outside of their area of use, in a header, for example, or before
their first use if they are used in multiple places in a file.

C states that struct types are compatible if they neither has a tag
name or they both have the same tag names, and if the is a one-to-one
relationship between the order, types, and names of their members.
That is guaranteed when there is one and only one definition of the
struct type, and it is in scope everywhere the type is used.

Presumably, somewhere else in another source or header file, is a
prototype and/or definition of a function whose address will
eventually be stored in the "free" member of a struct list. It will
need to have a definition of the structure type it accepts, which
probably comes from physically different text than the source of this
macro.

If somebody changes the definition of the struct type in one place or
the other, but not all places, then suddenly you have problems,
undefined behavior, "mysterious" defects, etc.

It would be much better to put the definition of struct Member in a
header, and include that header everywhere it is used.

--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
comp.lang.c http://c-faq.com/
comp.lang.c++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.learn.c-c++
http://www.club.cc.cmu.edu/~ajo/docs/FAQ-acllc.html
 
K

Kenneth Brody

James H. Newman said:
I am playing with some code that has been automatically generated
from ASN.1 data specification found in RFC 3280. One of the structures
generated reads as follows: [...snip...]
The preprocessor expands this as

typedef struct TBSCertList { [...]
struct revokedCertificates {
struct {
struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions *crlEntryExtensions;
asn_struct_ctx_t _asn_ctx;
} **array;
int count;
int size;
void (*free) (struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions * crlEntryExtensions;
asn_struct_ctx_t _asn_ctx;
} *);
} list; [...]
} TBSCertList_t;

This compiles all right, but the GCC compiler generates the
following warning:

TBSCertList.h:47: warning: structure defined inside parms
TBSCertList.h:47: warning: `struct Member' declared inside parameter list
TBSCertList.h:47: warning: its scope is only this definition or
declaration, which is probably not what you want

Line 47 is the line that reads

} ) list;

in the code above, before the preprocessing.
[...]

Look at this part in the middle of the macro expansion:
void (*free) (struct Member {
CertificateSerialNumber_t userCertificate;
Time_t revocationDate;
struct Extensions * crlEntryExtensions;
asn_struct_ctx_t _asn_ctx;
} *);

You are declaring a member of the struct called "free", which is
a function pointer, and you are prototyping that function. Within
that prototype, you are declaring a struct called "Member". This
"struct Member" is not the same "struct Member" that you define a
few lines earlier, because it is an actual definition, not just a
reference. (Yes, it is the same name and an identical layout, but
that doesn't matter as far as the warning is concerned.)

Consider this valid, though probably useless, snippet:

struct foo { int a; int b; };
extern void func1( struct foo *foopt );
extern void func2( struct foo { float a; float b; } *foopt );

Just as the third warning states:

its scope is only this definition or declaration, which is
probably not what you want

Change it so that the expansion is:

void (*free)(struct Member *);

--
+-------------------------+--------------------+-----------------------+
| Kenneth J. Brody | www.hvcomputer.com | #include |
| kenbrody/at\spamcop.net | www.fptech.com | <std_disclaimer.h> |
+-------------------------+--------------------+-----------------------+
Don't e-mail me at: <mailto:[email protected]>
 
K

Keith Thompson

Army1987 said:
That is about function parameters, not macro parameters.

The warning messages are about function parameters, not macro
parameters. The function parameter declaration happens to be within a
macro expansion, but that's irrelevant. (By the time the compiler
gets to the phase where it produces the warning, all macros have been
processed and are no longer visible.)
 
A

Army1987

Keith said:
The warning messages are about function parameters, not macro
parameters. The function parameter declaration happens to be within a
macro expansion, but that's irrelevant. (By the time the compiler
gets to the phase where it produces the warning, all macros have been
processed and are no longer visible.)
Oh, I had missed the declaration of free.
 
S

Stephen Sprunk

Jack Klein said:
[snip: excellent explanation of what the warning means]

If somebody changes the definition of the struct type in one place or
the other, but not all places, then suddenly you have problems,
undefined behavior, "mysterious" defects, etc.

It would be much better to put the definition of struct Member in a
header, and include that header everywhere it is used.

While I'd agree with all of the above if the code were maintained by a
human, it should be pointed out that the OP stated this code is
automatically generated. As long as one trusts that tool to keep the
definitions consistent (and in this example, it obviously does so), the code
is safe and the warning can be ignored or disabled. If the tool breaks,
you'll likely have far, far bigger problems than a simple compiler warning.

I'd, however, look into whether it's possible to modify the tool to generate
the code a bit more like a human would, i.e. in a way that doesn't trigger
this warning.

S
 
N

Neil Booth

Stephen said:
While I'd agree with all of the above if the code were maintained by a
human, it should be pointed out that the OP stated this code is
automatically generated. As long as one trusts that tool to keep the
definitions consistent (and in this example, it obviously does so), the
code is safe and the warning can be ignored or disabled. If the tool
breaks, you'll likely have far, far bigger problems than a simple
compiler warning.

I'd, however, look into whether it's possible to modify the tool to
generate the code a bit more like a human would, i.e. in a way that
doesn't trigger this warning.

No, such a prototype is broken because it is useless - it is impossible
to define or call a function declared in such a way that it defines
a new type in a conforming way. The compiler is entitled to (and many
do) reject such attempts.

Neil.
 
H

Harald van Dijk

[Structure declarations with function prototype scope]

No, such a prototype is broken because it is useless -

Almost, but not completely.
it is impossible
to define or call a function declared in such a way that it defines a
new type in a conforming way. The compiler is entitled to (and many do)
reject such attempts.

Exactly, and that gives it some actual use.

You're probably aware that function pointers can be converted to
different function pointers, and that no generic function pointer type
exists. For that reason, you can use something like void(*)(void) as a
generic function pointer type, and cast it whenever you want to use it.
That's great, except you might accidentally call the function -- there's
no reason for the compiler to reject fp(); if fp has that type, or even
warn about it. If you instead use void(*)(struct incomplete) as your
generic function pointer type, the compiler will not let you call the
function without a cast, because there's no way to pass an argument of
type struct incomplete.
 

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments. After that, you can post your question and our members will help you out.

Ask a Question

Members online

No members online now.

Forum statistics

Threads
473,995
Messages
2,570,236
Members
46,821
Latest member
AleidaSchi

Latest Threads

Top