convert binary data to int

[rubbishemail]

Hello,


I need to convert a 3 byte binary string like
"\x41\x00\x00" to 3 int values ( (65,0,0) in this case).
The string might contain characters not escaped with a \x, like
"A\x00\x00"


Any ideas?


Daniel

 

[Peter Otten]

I need to convert a 3 byte binary string like
"\x41\x00\x00" to 3 int values ( (65,0,0) in this case).
The string might contain characters not escaped with a \x, like
"A\x00\x00"

[ord(c) for c in "A\x00\x41"]

[65, 0, 65]

For more complex conversions look into the struct module.

Peter

 

[Laurent Pointal]

(e-mail address removed) a écrit :

Hello,


I need to convert a 3 byte binary string like
"\x41\x00\x00" to 3 int values ( (65,0,0) in this case).
The string might contain characters not escaped with a \x, like
"A\x00\x00"


Any ideas?

s = "\x41\x00\x00"
[ ord(c) for c in s ]

[65, 0, 0]

 

[Gabriel Genellina]

I need to convert a 3 byte binary string like
"\x41\x00\x00" to 3 int values ( (65,0,0) in this case).
The string might contain characters not escaped with a \x, like
"A\x00\x00"

py> [ord(x) for x in "\x41\x00\x00"]
[65, 0, 0]
py> [ord(x) for x in "A\x00\x00"]
[65, 0, 0]
py> "\x41\x00\x00" == "A\x00\x00"
True
py> "\x41\x00\x00" is "A\x00\x00"
True

(The last test is actually irrelevant, however)


--
Gabriel Genellina
Softlab SRL






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[rubbishemail]

[ord(x) for ...]
perfect, thank you


Daniel

 

[Paul Sijben]

in some cases struct.unpack would also help