convert ints in a range to strings

[hokieghal99]

Hi,

I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------

But, I get this error: cannot concatenate 'str' and 'int' objects. So, I
need to convert the ints in the range to strs, but I do not know how to
do that. Could someone help me? Ultimately, I want to print out
something like this to a text file:

192.168.1.0
192.168.1.1
192.168.1.2
....
192.168.1.255

Thanks!!!!

 

[Duncan Smith]

Hi,

I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------

But, I get this error: cannot concatenate 'str' and 'int' objects. So, I
need to convert the ints in the range to strs, but I do not know how to
do that. Could someone help me? Ultimately, I want to print out
something like this to a text file:

192.168.1.0
192.168.1.1
192.168.1.2
...
192.168.1.255

Thanks!!!!

I believe the second approach is generally faster.

Duncan

 

[Paul Rubin]

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r

for r in range(256):
print "192.168.1.%d" % r

 

[Heather Coppersmith]

Hi,
I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------

But, I get this error: cannot concatenate 'str' and 'int' objects. So, I
need to convert the ints in the range to strs, but I do not know how to
do that. Could someone help me? Ultimately, I want to print out
something like this to a text file:

192.168.1.0
192.168.1.1
192.168.1.2
...
192.168.1.255

Try any or all of these:

print a + b + c + str( r )

print a + b + c + "%d" % r

print a + b + c + "%s" % r

print "%s%s%s%d" % (a, b, c, r)

Regards,
Heather

 

[hokiegal99]

Thank you (Paul & Duncan) for showing me how to do this!

 

[hokiegal99]

Thanks Heather... this did it:

outputFile = file('ips.txt', 'w')
r = range(256)
for r in range(256):
f = '192.168.1.%s\n' % r #Change this line to macth your network.
outputFile.write(f)
outputFile.close()

 

[Michael Sweeney]

Hi,

I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r

You could try this:

a="192"
b="168"
c="1"
for d in range(256):
print "%s.%s.%s.%s"%(a,b,c,d)


192.168.1.0
192.168.1.1
192.168.1.2
192.168.1.3
....
192.168.1.255

- Mike

 

[Asun Friere]

Hi,

I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------

But, I get this error: cannot concatenate 'str' and 'int' objects. So, I
need to convert the ints in the range to strs, but I do not know how to
do that. Could someone help me? Ultimately, I want to print out
something like this to a text file:

192.168.1.0
192.168.1.1
192.168.1.2
...
192.168.1.255

Thanks!!!!

for x in r :
print a + b + c + str(x)


but why not use ints all the way along like this:

a = 192
b = 168
c = 1
for n in range(256) :
print "%d.%d.%d.%d" % (a, b, c, n)

or simply don't use them at all:

for n in range(256) :
print "192.168.1.%d" % n

 

[Raymond Hettinger]

[hokieghal99]

a="192."
b="168."
c="1."
r = range(256)
for r in r:

This rebinding of r is an amazing non-error.
I had to read it twice before I believed that it worked.
Working or not, don't do this. Changing the meaning
of variable like this drives some people off the edge
and they end up working in pure functional languages
and never recover.

print a + b + c + r

As the others pointed out, str(r) will do the trick.


Raymond Hettinger

 

[Duncan Smith]

Thanks Heather... this did it:

outputFile = file('ips.txt', 'w')
r = range(256)
for r in range(256):
f = '192.168.1.%s\n' % r #Change this line to macth your network.
outputFile.write(f)
outputFile.close()

[snip]

The second line of this code does nothing useful. My feeling is that as r
is an integer you should really use %d, rather than %s.

Duncan