A
Adgar Marks
Hi all,
I use linux OS. I would like to convert a file with the folloing format:
-rw-r--r-- 1 student student 11289 26. Jul 22:41 listing.txt
into FileName, Year, Month, Day
In order to do this, i would like to convert the month string from "Jul"
in to the number 7.
I wrote the following code:
def ConvertMonthToNumber(MonthStr)
case MonthStr
when "Jan" then 1
when "Feb" then 2
when "Mar" then 3
when "Apr" then 4
when "May" then 5
when "Jun" then 6
when "Jul" then 7
when "Aug" then 8
when "Sep" then 9
when "Okt" then 10
when "Nov" then 11
when "Dec" then 12
end
end
when i run this code, i get the following error:
SortList.rb:7: formal argument cannot be a constant
def ConvertMonthToNumber(MonthStr)
^
My questions are:
1. Is there already a function that does in Ruby?
2. How to correct this bug?
Thanks
I use linux OS. I would like to convert a file with the folloing format:
-rw-r--r-- 1 student student 11289 26. Jul 22:41 listing.txt
into FileName, Year, Month, Day
In order to do this, i would like to convert the month string from "Jul"
in to the number 7.
I wrote the following code:
def ConvertMonthToNumber(MonthStr)
case MonthStr
when "Jan" then 1
when "Feb" then 2
when "Mar" then 3
when "Apr" then 4
when "May" then 5
when "Jun" then 6
when "Jul" then 7
when "Aug" then 8
when "Sep" then 9
when "Okt" then 10
when "Nov" then 11
when "Dec" then 12
end
end
when i run this code, i get the following error:
SortList.rb:7: formal argument cannot be a constant
def ConvertMonthToNumber(MonthStr)
^
My questions are:
1. Is there already a function that does in Ruby?
2. How to correct this bug?
Thanks