Creating links with xsl from xml

schilde · Feb 13, 2004

Hello,

I want to transform a xml to html with xsl which is not this big
problem. But when I want to create a link with informations of the xml
it doesn't work. To illustrate the problem here an example:

link_example.xml

<booklist>
<book>
<id>1</id>
<title>blabla</title>
</book>
<book>
<id>2</id>
<title>blblblblbla</title>
</book>
</booklist>

The output should look like this. There are a list of links which
reference down to the titles in the same document:

Booklist: 1(as a link) 2(as link)

1 blabla
2 blblblblbla

<a href="{id}"><value-of select=".">..... didn't work. I don't know what
to do. Could someone help?

Greetings

Markus

Martin Honnen · Feb 13, 2004

schilde wrote:

I want to transform a xml to html with xsl which is not this big
problem. But when I want to create a link with informations of the xml
it doesn't work. To illustrate the problem here an example:

link_example.xml

<booklist>
<book>
<id>1</id>
<title>blabla</title>
</book>
<book>
<id>2</id>
<title>blblblblbla</title>
</book>
</booklist>

The output should look like this. There are a list of links which
reference down to the titles in the same document:

Booklist: 1(as a link) 2(as link)

1 blabla
2 blblblblbla

If I understand you correctly you want to process the <book> elements
twice, once to generate the list with links, once to generate the
detailed list with book titles. One way to do that is template with
modes so that an element can be processed in different modes, here is an
example:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl

utput method="html" encoding="utf-8" indent="yes" />

<xsl:template match="/">
<html>
<head>
<title>A list of books</title>
</head>
<body>
<div>
<p>Booklist:
<xsl:apply-templates select="booklist/book" mode="link" />
</p>
<div>
<ol>
<xsl:apply-templates select="booklist/book" />
</ol>
</div>
</div>
</body>
</html>
</xsl:template>

<xsl:template match="book">
<li id="b{position()}"><xsl:value-of select="title" /></li>
</xsl:template>

<xsl:template match="book" mode="link">
<a href="#b{position()}"><xsl:value-of select="position()" /></a>
<xsl:text> </xsl:text>
</xsl:template>

</xsl:stylesheet>

The resulting HTML is alike

<html>
<head>
<META http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>A list of books</title>
</head>
<body>
<div>
<p>Booklist:
<a href="#b1">1</a> <a href="#b2">2</a> <a
href="#b3">3</a> <a href="#b4">4</a> </p>
<div>
<ol>
<li id="b1">blabla</li>
<li id="b2">blblblblbla</li>
<li id="b3">Kibology for all</li>
<li id="b4">All for Kibology</li>
</ol>
</div>
</div>
</body>
</html>

Possible PHP/WP problem with code, trouble accessing custom archive links	1	Jan 5, 2023
Working on mobile css menu with plenty of frustration!	2	Dec 29, 2022
E-learning website with XML/XSL	1	Apr 1, 2009
Creating books with Sets	1	Sep 27, 2022
xsl not transforming correctly	2	Aug 29, 2006
Check forms With JavaScript	1	Mar 28, 2023
Only one table shows up with the information	2	Mar 29, 2023
How to add an element using XSL.	3	Sep 19, 2003

Creating links with xsl from xml

schilde

Martin Honnen

Ask a Question

Similar Threads

Members online

Forum statistics

Latest Threads