csv - how to parse a string, not a file?

[Alex Hunsley]

I've using the csv module to parse a string, not a file.
So how do I make a string look like a file so I can call csv.reader()
with it?

An an example, I'd like to call something like:

csvReader = csv.reader("1,2,3,4")

... but this direct attempt won't work as it expects a file or a handle...

thanks
alex

 

[John Lenton]

I've using the csv module to parse a string, not a file.
So how do I make a string look like a file so I can call csv.reader()
with it?

An an example, I'd like to call something like:

csvReader = csv.reader("1,2,3,4")

.. but this direct attempt won't work as it expects a file or a handle...

what is cStringIO?

 

[Foovoid Null]

import StringIO

csvReader = csv.reader(StringIO.StringIO("1,2,3,4"))

 

[Alex Hunsley]

what is cStringIO?

I'm not sure, but if you google there are answers:

http://www.google.com/search?hl=en&ie=UTF-8&q=cStringIO&btnG=Google+Search

alex

 

[Alex Hunsley]

import StringIO

csvReader = csv.reader(StringIO.StringIO("1,2,3,4"))

Much thanks! That does the job nicely..
alex

 

[John Lenton]

I'm not sure, but if you google there are answers:

http://www.google.com/search?hl=en&ie=UTF-8&q=cStringIO&btnG=Google+Search

sorry; I should stop giving answers as questions.

 

[Alex Hunsley]

sorry; I should stop giving answers as questions.

Oh, that was an answer! Sorry! I thought you were a newbie who had tried to
post a new topic but had just hit 'reply' or something like that...

 

[James Henderson]

Much thanks! That does the job nicely..
alex

I know this suggestion comes a bit late but

csvReader = csv.reader("1,2,3,4".splitlines(1))

may be a bit more efficient. csv.reader() does not actually require a
file-like object - any iterable will do, such as a list. The docstring is
explicit about this even though the online docs imply that the "csvfile"
object must have a next() method.

James