DateTime problem

[Cool Wong]

DateArray = ["Apr", "2", "2007"]

How can i read the month and year in the array???

The OUTPUT:
day = 01
month = 04
year = 07

 

[Mike Cahill]

teach-a-man-to-fish answer: check http://ruby-doc.org/stdlib/ , under Date

quick answer:
d = Date.civil(2007,4,2)
puts "OUTPUT:\n day = #{d.day}\n month=#{d.month}\n year=#{d.year}"

also try out puts d.strftime("%m %d %Y")


----- Original Message -----
From: "Cool Wong" <[email protected]>
Newsgroups: comp.lang.ruby
To: "ruby-talk ML" <[email protected]>
Sent: Tuesday, June 26, 2007 8:50 PM
Subject: DateTime problem

 

[Morton Goldberg]

DateArray = ["Apr", "2", "2007"]

How can i read the month and year in the array???

The OUTPUT:
day = 01
month = 04
year = 07

Something like this?

<code>
require "ParseDate"
DA = ["Apr", "2", "2007"]
args = ParseDate.parsedate("#{DA[1]} #{DA[0]} #{DA[2]}")
date = Time.local(*args).strftime(<<FMT)
\tday = %d
\tmonth = %m
\tyear = %y
FMT
puts date
</code>

<result>
day = 02
month = 04
year = 07
</resutl>

Regards, Morton

 

[Joel VanderWerf]

DateArray = ["Apr", "2", "2007"]

How can i read the month and year in the array???

The OUTPUT:
day = 01
month = 04
year = 07

Something like this?

<code>
require "ParseDate"
DA = ["Apr", "2", "2007"]
args = ParseDate.parsedate("#{DA[1]} #{DA[0]} #{DA[2]}")
date = Time.local(*args).strftime(<<FMT)
\tday = %d
\tmonth = %m
\tyear = %y
FMT
puts date
</code>

<result>
day = 02
month = 04
year = 07
</resutl>

Regards, Morton

Same idea, but slightly simpler...

da = ["Apr", "2", "2007"]
time = Time.parse(da.join(" "))
puts time.strftime(<<FMT)
\tday = %d
\tmonth = %m
\tyear = %y
FMT

__END__

Output:

day = 02
month = 04
year = 07

 

[Morton Goldberg]

Something like this?
<code>
require "ParseDate"
DA = ["Apr", "2", "2007"]
args = ParseDate.parsedate("#{DA[1]} #{DA[0]} #{DA[2]}")
date = Time.local(*args).strftime(<<FMT)
\tday = %d
\tmonth = %m
\tyear = %y
FMT
puts date
</code>
<result>
day = 02
month = 04
year = 07
</resutl>
Regards, Morton

Same idea, but slightly simpler...

da = ["Apr", "2", "2007"]
time = Time.parse(da.join(" "))
puts time.strftime(<<FMT)
\tday = %d
\tmonth = %m
\tyear = %y
FMT

__END__

Output:

day = 02
month = 04
year = 07

Yes, that's better. But don't you need a 'require "time"' at the
beginning? I needed it to make it work in my somewhat obsolescent
version of Ruby. Is it now part of the standard library?

Regards, Morton

 

[Joel VanderWerf]

Yes, that's better. But don't you need a 'require "time"' at the
beginning? I needed it to make it work in my somewhat obsolescent
version of Ruby. Is it now part of the standard library?

I think my irb required time ... (1.8.6).

 

[Alin Popa]

DateArray = ["Apr", "2", "2007"]

How can i read the month and year in the array???

The OUTPUT:
day = 01
month = 04
year = 07

Hi,

For me worked like that:

tt = Time.parse(da.join(" "))
day = tt.strtime("%d")
month = tt.strftime("%m")
year = tt.strftime("%y")

print "\nday #{day}"\
"\nmonth #{month}"
"\nyear #{year}"\
"\n"

Best regards,

Alin

 

[Karl von Laudermann]

The OUTPUT:
day = 01
month = 04
year = 07

I think you mean:
day = 01
month = 04
year = 2007

Have we learned nothing from Y2K?