Determine if email bounced back

[dw]

Hi. I accidentally posted this to the German version ("de") of this
newsgroup until I realized my mistake -- sorry!

We're using the subroutine below to send emails via our classic ASP
apps. However, we'd like to know if an email address isn't good -- in other
words, it bounced back. Is there a way to do that with the CDOSYS email
method? The From email is just some generic text and not a real email
address in our apps.

One brute force technique is to hit the Active Directory and see if the
email's on it. Is there any other way? Does the CDOSYS method throw any
errors that can be trapped? It sends emails to bad email addresses just as
quietly as to good ones. Thanks.


Sub
sendMail_CDOSYS(prmMailFrom,prmMailTo,prmMailCC,prmMailSubject,prmMailBody)
Dim objCDOSYSMail, objCDOSYSCon

Set objCDOSYSMail = Server.CreateObject("CDO.Message")
Set objCDOSYSCon = Server.CreateObject ("CDO.Configuration")

With objCDOSYSCon
.Fields("http://schemas.microsoft.com/cdo/configuration/smtpserver") =
"myExchangeServer.myDomain.com"
.Fields("http://schemas.microsoft.com/cdo/configuration/smtpserverport")
= 25
.Fields("http://schemas.microsoft.com/cdo/configuration/sendusing") = 2
.Fields("http://schemas.microsoft.com/cdo/configuration/smtpconnectiontimeout")
= 60
.Fields.Update
End With

With objCDOSYSMail
Set .Configuration = objCDOSYSCon
.From = prmMailFrom
.To = prmMailTo
If Not IsNull(prmMailCC) And Len(Trim(prmMailCC)) > 0 Then .CC =
prmMailCC ' If there is a CC passed in, set the CC field to it.
.Subject = prmMailSubject
.HTMLBody = prmMailBody
.Send
End With

Set objCDOSYSMail = Nothing
Set objCDOSYSCon = Nothing
End Sub

 

[Adrienne Boswell]

One brute force technique is to hit the Active Directory and see if
the email's on it. Is there any other way? Does the CDOSYS method
throw any errors that can be trapped? It sends emails to bad email
addresses just as quietly as to good ones. Thanks.

You can take a look at <http://centralops.net/co/EmailDossier.vbs.asp> and
see if that might help you.