difference between inheritance and mixin

V

Vellingiri Arul

Hai friends,
Can anybody can answer this question.
what is the difference between inheritance and mixin.
what is the use of mixin and what is the use of inheritance.

Inheritance is we are deriving the superclass.
for example,I did like this,

cass A
def B
puts 'a and b'
end
end
class C < A
def D
puts 'd'
end
end
e=C.new
e.B
e.D
The output should be like this,
a and b
d
I know very vell about the inheritance,but both the
cases we are using but Idon't about the mixin and difference two
methods.

by
vellingiri
 
7

7stud --

what is the use of mixin and what is the use of inheritance

"Programming Ruby (2nd)" :

p 119:
In fact, mixed-in modules effectively behave as superclasses."


p. 355:
If a module is included in a class definition, the module's constants,
class variables, and instance methods are effectively bundled into an
anonymous(and inaccessible) superclass for that class....Calls to
methods not defined in the class will be passed to the module(s) mixed
into the class before being passed to any parent class.


module Greet
def friendly_greet
puts "Hello."
end

def angry_greet
puts "Go away."
end

end

class NicePerson
include Greet
end

class MadPerson
include Greet
end

class SadPerson
include Greet

def friendly_greet
puts "Cry, hi, cry."
end

end

np = NicePerson.new
np.friendly_greet #Hello.
puts

mp = MadPerson.new
np.angry_greet #Go away.
puts

sp = SadPerson.new
sp.friendly_greet #Cry, hi, cry.
sp.angry_greet #Go away.
 
P

Phrogz

Hai friends,
Can anybody can answer this question.
what is the difference between inheritance and mixin.
what is the use of mixin and what is the use of inheritance.

Mixin modules are searched before the parent class.
http://phrogz.net/RubyLibs/RubyMethodLookupFlow.png

Also, you can only inherit from one parent class, but you can mixin
many modules to the same class.

Because modules cannot inherit from other modules or classes, there is
no problem of 'diamond' inheritance.
 
7

7stud --

what is the use of mixin and what is the use of inheritance

1)
class FourLeggedAnimal
def speed
puts "I run fast."
end
end

class Mammal
def birth
puts "My babies don't hatch from eggs."
end
end

class Dog < FourLeggedAnimal
def speak
puts "Bark, bark."
end
end

d = Dog.new
d.speak
d.speed
d.birth

--output:--
Bark, bark.
I run fast.
r6test.rb:21: undefined method `birth' for #<Dog:0x251ac>
(NoMethodError)


2)
class FourLeggedAnimal
def speed
puts "I run fast."
end
end

module Mammal
def birth
puts "My babies don't hatch from eggs."
end
end

class Dog < FourLeggedAnimal
include Mammal

def speak
puts "Bark, bark."
end
end

d = Dog.new
d.speak
d.speed
d.birth

--ouput:--
Bark, bark.
I run fast.
My babies don't hatch from eggs.
 
D

David A. Black

Hi --

Mixin modules are searched before the parent class.
http://phrogz.net/RubyLibs/RubyMethodLookupFlow.png

Also, you can only inherit from one parent class, but you can mixin
many modules to the same class.

Because modules cannot inherit from other modules or classes, there is
no problem of 'diamond' inheritance.

Modules can mix in modules, though, so you could have:

module M

module N module O

class C


But the diamond problem is avoided by having the order of mixing in be
significant, so that there's no ambiguity about which module/class is
to be searched.


David

--
Upcoming training from Ruby Power and Light, LLC:
* Intro to Ruby on Rails, Edison, NJ, October 23-26
* Advancing with Rails, Edison, NJ, November 6-9
Both taught by David A. Black.
See http://www.rubypal.com for more info!
 
R

Rick DeNatale

Hi --



Modules can mix in modules, though, so you could have:

module M

module N module O

class C


But the diamond problem is avoided by having the order of mixing in be
significant, so that there's no ambiguity about which module/class is
to be searched.

On the other hand, Ruby has varied semantics for different versions
of structures like this:

Module M
\
Class C
|
Class D
Module M |
\ |
Class E

If M defines a method m and D overrides m, it's version dependent
which definition instances of E get. At least for a while in the 1.9
history, it would get the original version back, which seems to be the
'correct' semantics to me. Last time I checked though 1.9 went back
to ignoring the re-inclusion.
 

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