document function - help

D

duzy

This line gets corect information,
<xsl:value-of
select="document('park1.xml')/episode_guide/season[last()]/@no"/>
but i need to get this information from 47 files (park1, park2, park3,
........ , park47).
Have I to write 47 lines of code?
I cant find any loop able to work here.

Thanks
Duzy
 
D

David Carlisle

so long as your source doc has at least 47 nodes

<xsl:for-each select="(//node())[position()&lt;f8]">
<xsl:value-of
select="document(concat('park',position(),'.xml'))"/zzzzz"/>
....

David
 

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