Does Python provide "Struct" data structure?

[Daniel Mark]

Hello all:

I have found a useful module in IPython, named 'from IPython.ipstruct
import Struct".

So I can use it as follows:

####################################
from IPython.ipstruct import Struct

mystruct = Struct(echo = 1,
verb = 'Verbose',
filedir = 'C:/temp',
)

print mystruct.filedir
#####################################

I have two following questions:

1> Does Python provide such Struct in this standard libary.
Python has "4.3 struct -- Interpret strings as packed binary data", but
it looks like different
from what I really want to get.

2> Is it safe to use IPython's modules in my python program?
I will pack all my code into an executable application by using py2exe.
The clients would like to use this application without any python
intallation.
What should I pay attention if I include the IPython modules into my
python code and
convert it into executable application by using py2exe?

The setup.py for my application is as follows:
###########################################
from distutils.core import setup
import py2exe

options = {
"bundle_files": 1,
# "ascii": 1, # to make a smaller executable, don't include the
encodings
"compressed": 1, # compress the library archive
}

setup(
# The first three parameters are not required, if at least a
# 'version' is given, then a versioninfo resource is built from
# them and added to the executables.
version = "1.0",
description = "mycode",
name = "mycode",

options = {"py2exe": options},
zipfile = None, # append zip-archive to the executable.

# targets to build
console=['mycode.py'],
)
###################################################

Does I need to make any modification if I include IPython module in my
code?

Thank you for your helps
-Daniel

 

[jay graves]

I have found a useful module in IPython, named 'from IPython.ipstruct
import Struct".
So I can use it as follows:
####################################
from IPython.ipstruct import Struct

mystruct = Struct(echo = 1,
verb = 'Verbose',
filedir = 'C:/temp',
)

print mystruct.filedir
#####################################

Does 'Bunch' fit the bill?
http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/52308

....
jay graves

 

[Bjoern Schliessmann]

I have two following questions:

1> Does Python provide such Struct in this standard libary.
Python has "4.3 struct -- Interpret strings as packed binary
data", but it looks like different from what I really want to get.

Yes, that module is used when you want to deal with C structs in
binary form (e.g. useful at networking with binary protocols).

Try using dictionaries or custom, field-only class instances
as "struct".

Regards,


Björn

 

[MonkeeSage]

Hi Daniel,

To avoid problems you could vendor the ipython file you require, but an
easier solution may just be to implement your own version of the class
(it's extreemly easy):

class struct():
def __init__(self, *args, **kwargs):
for k, v in kwargs.items():
setattr(self, k, v)

mystruct = struct(echo = 1,
verb = 'Verbose',
filedir = 'C:/temp')

print mystruct.filedir

Regards,
Jordan

 

[Brian Blais]

1> Does Python provide such Struct in this standard libary.
Python has "4.3 struct -- Interpret strings as packed binary data", but
it looks like different
from what I really want to get.

I like the following version:

class Struct(dict):

def __getattr__(self,name):

try:
val=self[name]
except KeyError:
val=super(Struct,self).getattr(self,name)

return val

def __setattr__(self,name,val):

l=dir(self)

if name in self:
super(Struct,self).setattr(self,name,val)
else:
self[name]=val


it has the added benefit of having all of the dict methods too.


bb