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C Programming
e to the i pi
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[QUOTE="¬a\\/b, post: 2507014"] my book says if a, beR a+i*b=r(cos(t)+i*sin(t))=r*e^(i*t) (r,t)eRx[0,2*pi) if i have a+i*b than find r=sqrt(a^2+b^2) if r=0 than a+i*b=0*e^0 else resolve cos(t)=a/r sin(t)=b/r te[0, 2*pi) (note 1=a^2/r^2+b^2/r^2=cos(t)^2+sin(t)^2) and write a+i*b=r*e^(i*t) if i have r*e^(i*t)=r(cos(t)+i*sin(t))= r*cos(t)+i*r*sin(t)=a+i*b it seems right "e^(i*5*pi/2) = i" seems to me wrong because not(5*pi/2e[0,2pi)) [/QUOTE]
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