Exceptions

[DavidPorterHolt]

Can anyone explain why the second print statement below (copied from
'Dive Into Python') generates a syntax error? As I understand
exceptions, the except block should handle the exception, and the
following print statement should execute normally.
fsock = open('/nothere')
except IOError:
print 'The file does not exist, exiting gracefully'
print 'This line will always print'
SyntaxError: invalid syntax
Any help will be much appreciated.

Thanks,
David Holt
(e-mail address removed)

 

[DavidPorterHolt]

Here's the same clip, but run in the command line interpreter. The
error gives a little more info.
.... fsock = open('/notthere')
.... except IOError:
.... print 'The file does not exist, exiting gracefully'
.... print 'This line will always print'
File "<stdin>", line 5
print 'This line will always print'
^
SyntaxError: invalid syntax
Thanks,
David Holt
(e-mail address removed)

 

[Paul McGuire]

Here's the same clip, but run in the command line interpreter. The
error gives a little more info.

... fsock = open('/notthere')
... except IOError:
... print 'The file does not exist, exiting gracefully'
... print 'This line will always print'
File "<stdin>", line 5
print 'This line will always print'
^
SyntaxError: invalid syntax

Thanks,
David Holt
(e-mail address removed)

In the interpreter, after an indented group (such as your except IOError
block), you have to enter a blank line, THEN enter the 2nd print statement:
.... fsock = open('/notthere')
.... except IOError:
.... print 'The file does not exist, exiting gracefully'
....
The file does not exist, exiting gracefully
(Note the empty ellipsis, indicating a line with no more indention.)

-- Paul

 

[DavidPorterHolt]

That's good to know. Thanks.