file access dialog

[Wouter van Ooijen]

I have a tool in Python to which I want to add a small GUI. The tools
currently runs everywhere PySerial is supported. I need a file-access
dialog. What is the preffered way to to this? Is there a
platform-independent file-access dialog available, or should I use the
windows native version when running on windows (and how do I do that)?


Wouter van Ooijen

-- ------------------------------------
http://www.voti.nl
Webshop for PICs and other electronics
http://www.voti.nl/hvu
Teacher electronics and informatics

 

[Fredrik Lundh]

I have a tool in Python to which I want to add a small GUI. The tools
currently runs everywhere PySerial is supported. I need a file-access
dialog. What is the preffered way to to this? Is there a
platform-independent file-access dialog available, or should I use the
windows native version when running on windows (and how do I do that)?

depends on what GUI toolkit you prefer to use.

for Tkinter (which is available on most modern platforms), see "File
Dialogs" on this page:

http://www.pythonware.com/library/tkinter/introduction/x1164-data-entry.htm

the following thread may also be helpful:

http://tinyurl.com/b2zxb

</F>

 

[Eric Brunel]

I have a tool in Python to which I want to add a small GUI. The tools
currently runs everywhere PySerial is supported. I need a file-access
dialog. What is the preffered way to to this? Is there a
platform-independent file-access dialog available, or should I use the
windows native version when running on windows (and how do I do that)?

Tkinter has a file acces dialog available with the same API on all platforms. It is also mapped to the standard dialog on Windows. Since Tkinter is certainly installed by default with Python, if a file dialog is everything you need, you probably don't have to look further.

To use the dialog, just do:

from Tkinter import Tk
from tkFileDialog import askopenfilename
## Tk needs a main window to work, so create one and hide it
root = Tk()
root.withdraw()
## Ask the file name
fileName = askopenfilename(filetypes=[('Python files', '*.py'), ('All files', '*')])
if fileName:
print 'open', fileName
else:
print 'cancelled'
## Over
root.destroy()

HTH

 

[utabintarbo]

For simple, it's hard to beat EasyGUI: http://www.ferg.org/easygui/

Bob

 

[Wouter van Ooijen]

Tkinter has a file acces dialog available with the same API on all platforms. It is also mapped to the standard dialog on Windows.

Since Tkinter is certainly installed by default with Python, if a file dialog is everything you need, you probably don't have to look further.

Great


Wouter van Ooijen

-- ------------------------------------
http://www.voti.nl
Webshop for PICs and other electronics
http://www.voti.nl/hvu
Teacher electronics and informatics