For Loop

[shapper]

Hello,

I don't know PERL and I need to convert a simple code to C# or VB.NET.

Could someone, please, help me with the conversion?
A description of how the loop works would be enough.

for $row (1..$h)
{ for ($s=0,$i=$row; $s<$c; $i+=($h+($s<$rm)), ++$s)
{ printf "%7u", $i }
print "\n";

}

++$h;
for ($s=0,$i=$h; $s < $rm; $i+=$h, ++$s)
{ printf "%7u", $i }

Thanks,
Miguel

 

[Paul Lalli]

I don't know PERL

Perl. Not PERL.

and I need to convert a simple code to C# or VB.NET.

Could someone, please, help me with the conversion?
A description of how the loop works would be enough.

for $row (1..$h)

This will loop through the numbers 1 through $h, incrementing by 1
each time, and each iteration setting $row to be the current value.
So if, for example, $h was 5, this would loop five times, setting $row
to 1, 2, 3, 4, and 5, in turn.

{ for ($s=0,$i=$row; $s<$c; $i+=($h+($s<$rm)), ++$s)

This starts $s at 0 and $i at whatever $row is in this iteration. It
continues to loop so long as $s is less than $c. At the end of each
iteration, it increments $s by 1, and adds $h to $i. If $s is less
than $rm, it will add an aditional 1 to $i.

{ printf "%7u", $i }

This prints the current value of $i, padded to 7 spaces.

print "\n";

This prints a newline.

}

++$h;

Increment $h by one.

for ($s=0,$i=$h; $s < $rm; $i+=$h, ++$s)

Starts $s at 0, $i at $h. Loops while $s is less than $rm. At the
end of each iteration, adds $h to $i, and increments $s by 1.

{ printf "%7u", $i }

Prints the current value of $i, again padded 7 spaces.

Thanks,

You're welcome.

Paul Lalli

 

[Tad McClellan]

I don't know PERL

We can tell, because you did not spell "Perl" correctly.

and I need to convert a simple code to C# or VB.NET.

Could someone, please, help me with the conversion?
A description of how the loop works would be enough.

Descriptions of Perl syntax are in the perlsyn.pod documentation:

perldoc perlsyn

for $row (1..$h)

That one is covered in the "Foreach Loops" section.

{ for ($s=0,$i=$row; $s<$c; $i+=($h+($s<$rm)), ++$s)

That one is covered in the "For Loops" section.

 

[Dr.Ruud]

Paul Lalli schreef:

shapper:

{ for ($s=0,$i=$row; $s<$c; $i+=($h+($s<$rm)), ++$s)

[...] At the end of each
iteration, it increments $s by 1, and adds $h to $i. If $s is less
than $rm, it will add an aditional 1 to $i.

The behaviour of $s could well be undefined (un-guaranteed) there.
Because of the comma-operator, I would expect that the ++$s is done
*after* $i is updated.

 

[shapper]

Paul Lalli schreef:

shapper:

[...] At the end of each
iteration, it increments $s by 1, and adds $h to $i. If $s is less
than $rm, it will add an aditional 1 to $i.

The behaviour of $s could well be undefined (un-guaranteed) there.
Because of the comma-operator, I would expect that the ++$s is done
*after* $i is updated.

Hi,

I tried to convert the code but until now I wasn't success ... I am
maybe doing something wrong here.

Does anyone knows what would be the equivalent code in C# or VB.NET?

Thanks,
Miguel

 

[Paul Lalli]

I tried to convert the code but until now I wasn't success ... I am
maybe doing something wrong here.

Undoubtedly you are, but you didn't show any code for anyone to tell
you *what* you're doing wrong.

Does anyone knows what would be the equivalent code in C# or
VB.NET?

You've been told what the Perl code does. If you don't know how to
translate the English algorithm into C# or VB.NET code, then you have
a C# and/or VB.NET problem, not a Perl problem. You are far more
likely to receive good answers to this query in a newsgroup devoted to
C# or VB.NET.

Paul Lalli

 

[John W. Krahn]

We can tell, because you did not spell "Perl" correctly.

The OP *spelt* it correctly, they just didn't capitalize it correctly.


John

 

[Ian Wilson]

I tried to convert the code but until now I wasn't success ... I am
maybe doing something wrong here.

Does anyone knows what would be the equivalent code in C# or VB.NET?

I'd post in a C# newsgroup, quoting Paul's explanation of the Perl, also
cut & paste the C# you have written, state what output you get, state
why you think the output is wrong and ask for suggestions.

I'd try newsgroup microsoft.public.dotnet.languages.csharp.

 

[Skye Shaw!@#$]

Hello,

I don't know PERL and I need to convert a simple code to C# or VB.NET.

I'm sorry

Could someone, please, help me with the conversion?
A description of how the loop works would be enough.

for $row (1..$h)
{ for ($s=0,$i=$row; $s<$c; $i+=($h+($s<$rm)), ++$s)
{ printf "%7u", $i }
print "\n";

}

++$h;
for ($s=0,$i=$h; $s < $rm; $i+=$h, ++$s)
{ printf "%7u", $i }

for $row (1..$h)
For Row=1 To H 'VB
for( int row=1; row<h; row++ ) //C#

printf "%7u", $i
Console.WriteLine("{07}",i) //.NoT

 

[Brad Baxter]

I'm sorry


for $row (1..$h)
For Row=1 To H 'VB
for( int row=1; row<h; row++ ) //C#

printf "%7u", $i
Console.WriteLine("{07}",i) //.NoT

for( int row=1; row<=h; row++ ) //C#