free store new double[]

[Hicham Mouline]

hi,

Is there a way to allocate an array and initialize in the same statement?

double* d = new double[n];
and assign immediately a value, say NaN

what i'm doing now is just:

for (size_t i=0; i<n; ++i)
d = NaN;

regards,

 

[Maxim Yegorushkin]

Is there a way to allocate an array and initialize in the same statement?

double* d = new double[n];
and assign immediately a value, say NaN

what i'm doing now is just:

for (size_t i=0; i<n; ++i)
  d = NaN;

Another way:

double* d = std::fill_n(new double[n], n, NaN) - n;

Or (save a subtraction):

double* d;
std::fill_n((d = new double[n]), n, NaN);

 

[Andrey Tarasevich]

hi,

Is there a way to allocate an array and initialize in the same statement?

double* d = new double[n];
and assign immediately a value, say NaN

If you were looking for zeroes, the you could just do

double* d = new double[n]();

what i'm doing now is just:

for (size_t i=0; i<n; ++i)
d = NaN;

Otherwise, to meet your "one statement" requirement, the only thing you
can do is replace you explicit cycle with a standard (or your own)
function with equivalent functionality.