func(*params)

[David Duerrenmatt]

Hi there

For some reasons, I've to use Python 1.5.2 and am looking for a workaround:

In newer Python versions, I can call a function this way:

func = some_function
func(*params)

Then, the list/tuple named params will automatically be "expanded" and
n=len(params) arguments will be submitted.

Python 1.5.2 doesn't support this kind of function call. I could use
some workaround like:

func(params[0],params[1]...)

but since the number of items in params varies and depends on the mapped
function "some_function", this isn't a good solution.

Another idea is to use exec(), don't know whether this is safe...

Any recommondations or tricks?


Thanks,
david

 

[Peter Otten]

For some reasons, I've to use Python 1.5.2 and am looking for a
workaround:

In newer Python versions, I can call a function this way:

func = some_function
func(*params)

Use

apply(func, params)

Peter

 

[Nick Smallbone]

Hi there

For some reasons, I've to use Python 1.5.2 and am looking for a workaround:

In newer Python versions, I can call a function this way:

func = some_function
func(*params)

I think the "apply" function is what you want:

apply(object[, args[, kwargs]]) -> value

Call a callable object with positional arguments taken from the tuple
args, and keyword arguments taken from the optional dictionary kwargs.
Note that classes are callable, as are instances with a __call__()
method.

Deprecated since release 2.3. Instead, use the extended call syntax:
function(*args, **keywords).

 

[Fredrik Lundh]

For some reasons, I've to use Python 1.5.2 and am looking for a workaround:

In newer Python versions, I can call a function this way:

func = some_function
func(*params)

Then, the list/tuple named params will automatically be "expanded" and
n=len(params) arguments will be submitted.

Python 1.5.2 doesn't support this kind of function call.

use

apply(func, params)

or

result = apply(func, params)

more info:
Help on built-in function apply in module __builtin__:

apply(...)
apply(object[, args[, kwargs]]) -> value

Call a callable object with positional arguments taken from the tuple args,
and keyword arguments taken from the optional dictionary kwargs.
Note that classes are callable, as are instances with a __call__() method.

Deprecated since release 2.3. Instead, use the extended call syntax:
function(*args, **keywords).

</F>

 

[David Duerrenmatt]

Great, this is exactly what I was looking for.

Thanks all of you for your immediate answer!

Hi there

For some reasons, I've to use Python 1.5.2 and am looking for a workaround:

In newer Python versions, I can call a function this way:

func = some_function
func(*params)

I think the "apply" function is what you want:

apply(object[, args[, kwargs]]) -> value

Call a callable object with positional arguments taken from the tuple
args, and keyword arguments taken from the optional dictionary kwargs.
Note that classes are callable, as are instances with a __call__()
method.

Deprecated since release 2.3. Instead, use the extended call syntax:
function(*args, **keywords).