Function pointers and inline definitions

[raphfrk]

This is probably not possible, but I thought I would ask.

Assuming that there is a function that takes a pointer to a function
as an input. Can the passed function be defined inline.

For example:

void func_func( void (*func_tst)( int ) , int a )
{

(*func_tst)( a );

}

int main( int argc, char **argv )
{

func_func(
(void (*) (int a))
{
printf( "%n" , a );
},
7
);

}

The effect would be that func_func would call the inlined function and
pass it 7.

 

[Ben Bacarisse]

This is probably not possible, but I thought I would ask.

Assuming that there is a function that takes a pointer to a function
as an input. Can the passed function be defined inline.

When I read this, I though "yes" because a "function defined inline"
might mean a function whose definition includes the qualifier "inline"
and that is possible. However...

For example:

void func_func( void (*func_tst)( int ) , int a )
{

(*func_tst)( a );

}

int main( int argc, char **argv )
{

func_func(
(void (*) (int a))
{
printf( "%n" , a );
},
7
);

}

The effect would be that func_func would call the inlined function and
pass it 7.

No, not possible. I'd call this a "function literal" rather than an
inlined function but, whatever you call it, you can't do it in
standard C.

 

[raphfrk]

No, not possible. I'd call this a "function literal" rather than an
inlined function but, whatever you call it, you can't do it in
standard C.

Bah . Thanks for the info.