gsub

[Tomas Fischer]

Hi,

I have a string s= XXaaXX, in which i want to replace the last substring
r, which is determined at run time.

r= XX

s.gsub(/XX\z/,'') solves the problem in a static way.
s.gsub(r,'') solves it too, but who can I specify, that only the last
occurence should be replaced.

Best regards,
Tomas

 

[Vincent Fourmond]

Hello !

s.gsub(/XX\z/,'') solves the problem in a static way.
s.gsub(r,'') solves it too, but who can I specify, that only the last
occurence should be replaced.

Would
s.gsub(/#{r}$/,'')
do what you want ?

Vince

 

[Matthew Harris]

Alternatively you can reverse, sub, reverse, but I like Vince's way.

 

[James Edward Gray II]

Hello !


Would
s.gsub(/#{r}$/,'')
do what you want ?

If that's for a single line string, drop the g and just use sub().

James Edward Gray II

 

[Tomas Fischer]

Hi,

thanks for your solutions. But I've forgotten to mention, that r can
contain brackets, so the simple way s.gsub(/#{r}$/,'') doesn't work.

I use now the reverse, sub approach.

Best regards,
Tomas