[HELP] modifying hash

[Bil Kleb]

I've got a mental block on refactoring the following,

# given a hash of arrays,
hash = { 1=>[:a,:b,:c], 2=>[:d,:e], 3=>[:a,:c] }

# remove a specified element from the arrays if present
hash.each{ |k,v| hash[k] = v.delete_if{|e| e==:a} }

=> { 1=>[:b,:c], 2=>[:d,:e], 3=>[:c] }

Isn't there a simpler way to remove the matching
elements? (Maybe my data structure is just lame?)

Thanks,

 

[Bil Kleb]

I've got a mental block on refactoring the following,

hash.each{ |k,v| hash[k] = v.delete_if{|e| e==:a} }

Broke the block?

hash.each_value{ |v| v.delete :a }

Later,

 

[David A. Black]

Hi --

I've got a mental block on refactoring the following,

# given a hash of arrays,
hash = { 1=>[:a,:b,:c], 2=>[:d,:e], 3=>[:a,:c] }

# remove a specified element from the arrays if present
hash.each{ |k,v| hash[k] = v.delete_if{|e| e==:a} }

=> { 1=>[:b,:c], 2=>[:d,:e], 3=>[:c] }

Isn't there a simpler way to remove the matching
elements? (Maybe my data structure is just lame?)

Slightly simpler:

hash.values.each {|v| v.deletea) }


David

 

[Ralf Müller]

hash.each{ |k,v| hash[k] = v.delete_if{|e| e==:a} }

What about
hash.each{ |k,v| v.delete_if{|e| e==:a} }
?
--

 

[nobu.nokada]

Hi,

At Wed, 21 Sep 2005 21:01:52 +0900,
David A. Black wrote in [ruby-talk:156926]:

hash.values.each {|v| v.deletea) }

Hash#each_value would be better.