Help with paths

[Devin M]

Hello, I am using os.path to get the absolute paths of a few
directories that some python files are in.
FIlePath = os.path.dirname(os.path.realpath(__file__))
which returns a path similar to /home/devinm/project/files
Now I want to get the directory above this one. (/home/devinm/
project/) Is there a simple way to do this? I was considering spliting
apart the path and then reconstructing it with the last folder left
off. Hope theres a better way to do this.

Regards,
Devin M

 

[Andreas Waldenburger]

Hello, I am using os.path to get the absolute paths of a few
directories that some python files are in.
FIlePath = os.path.dirname(os.path.realpath(__file__))
which returns a path similar to /home/devinm/project/files
Now I want to get the directory above this one. (/home/devinm/
project/) Is there a simple way to do this? I was considering spliting
apart the path and then reconstructing it with the last folder left
off. Hope theres a better way to do this.

Maybe os.relpath("..", FilePath) ? Python > 2.6 only.

Don't know if that does what you want, but from the description, it
seems to fit:

<http://docs.python.org/library/os.path.html>

os.path.relpath(path[, start])

Return a relative filepath to path either from the current
directory or from an optional start point.

start defaults to os.curdir.


/W

 

[Andreas Waldenburger]

[snip]

Maybe os.relpath("..", FilePath) ? Python > 2.6 only.

Gah! I should learn to copy&paste more. Obviously it's the second one
(os.path.relpath), not the first.

/W

 

[Chris Rebert]

Hello, I am using os.path to get the absolute paths of a few
directories that some python files are in.
FIlePath = os.path.dirname(os.path.realpath(__file__))
which returns a path similar to /home/devinm/project/files
Now I want to get the directory above this one. (/home/devinm/
project/) Is there a simple way to do this?

parent_dir = os.path.split(FilePath)[0]

Note that os.split() does not work like str.split().
Also, don't use CamelCase for non-classes.

Cheers,
Chris

 

[Emile van Sebille]

On 10/18/2010 2:24 PM Devin M said...

Hello, I am using os.path to get the absolute paths of a few
directories that some python files are in.
FIlePath = os.path.dirname(os.path.realpath(__file__))
which returns a path similar to /home/devinm/project/files
Now I want to get the directory above this one. (/home/devinm/
project/) Is there a simple way to do this? I was considering spliting
apart the path and then reconstructing it with the last folder left
off. Hope theres a better way to do this.

Yes -- in the same module...
'C:\\Python26\\lib'

 

[Alexander Kapps]

Hello, I am using os.path to get the absolute paths of a few
directories that some python files are in.
FIlePath = os.path.dirname(os.path.realpath(__file__))
which returns a path similar to /home/devinm/project/files
Now I want to get the directory above this one. (/home/devinm/
project/) Is there a simple way to do this? I was considering spliting
apart the path and then reconstructing it with the last folder left
off. Hope theres a better way to do this.

Regards,
Devin M

os.path.split() is designed for this

In [4]: path="/home/devinm/project/files"

In [5]: import os.path

In [6]: os.path.split(path)[0]
Out[6]: '/home/devinm/project'

 

[Devin M]

Hello, I am using os.path to get the absolute paths of a few
directories that some python files are in.
FIlePath = os.path.dirname(os.path.realpath(__file__))
which returns a path similar to /home/devinm/project/files
Now I want to get the directory above this one. (/home/devinm/
project/) Is there a simple way to do this? I was considering spliting
apart the path and then reconstructing it with the last folder left
off. Hope theres a better way to do this.

Regards,
Devin M

os.path.split() is designed for this

In [4]: path="/home/devinm/project/files"

In [5]: import os.path

In [6]: os.path.split(path)[0]
Out[6]: '/home/devinm/project'

Thank you for the help