L
listrecv
Any ideas on using Hibernate OR/M from within Ruby?
T
Trans
Why, when you have Og, ActiveRecord and a few other interesting
choices?
T.
choices?
T.
L
listrecv
ActiveRecord is great for small-to-medium things, but does quickly show
it's limits on large things. NOTE: Please, do not turn this thread
into a flame war. See Martin Fowler's discussion of ActiveRecord
versus DataMapper. Rails's ActiveRecord is based on Fowler's
ActiveRecord pattern, wheras Hibernate is a DataMapper, which Fowler
himself favors for complicated mappings.
See DHH's post:
"No, you don't get the full offer of opportunities that straight OO
with a data mapper holds. I'd like to think, though, that Active Record
gives you 80% of the features for 20% of the effort."
http://www.loudthinking.com/arc/000209.html
Example for me:
Let's say I have a class hierarchy, in which a particular field is
stored direclty in the db for one class, and calculated using a simple
SQL formula for other other classes. How can I use the DB to query the
tree for all objects where field == aVal.
Answer: In ActiveRecord - you can't (w/o major hacking). You need to
instantiate each one from the db, and then use Ruby to check each one.
it's limits on large things. NOTE: Please, do not turn this thread
into a flame war. See Martin Fowler's discussion of ActiveRecord
versus DataMapper. Rails's ActiveRecord is based on Fowler's
ActiveRecord pattern, wheras Hibernate is a DataMapper, which Fowler
himself favors for complicated mappings.
See DHH's post:
"No, you don't get the full offer of opportunities that straight OO
with a data mapper holds. I'd like to think, though, that Active Record
gives you 80% of the features for 20% of the effort."
http://www.loudthinking.com/arc/000209.html
Example for me:
Let's say I have a class hierarchy, in which a particular field is
stored direclty in the db for one class, and calculated using a simple
SQL formula for other other classes. How can I use the DB to query the
tree for all objects where field == aVal.
Answer: In ActiveRecord - you can't (w/o major hacking). You need to
instantiate each one from the db, and then use Ruby to check each one.
E
Eero Saynatkari
List said:
Google up Og and Kansas and see if either suits you better.
Both take a modeling approach perpendicular to AR. There
are others also, I am sure.
Or, of course, you could restructure your data
E
Z
Zed A. Shaw
Google up Og and Kansas and see if either suits you better.
Both take a modeling approach perpendicular to AR. There
are others also, I am sure.
Or, of course, you could restructure your data
No, that'd actually involve admitting he is wrong. The day a
programmer actually admits he's wrong is the day Satan ice skates
around Times Square in July eating Tasti-Delight while wearing long
underwear.
For another great example of "fighting to always be right" refer to any
thread about plural table names (either side).
Zed A. Shaw
http://www.zedshaw.com/
N
Neil Stevens
Zed said:
Yeah, that's the way, go off on a tangent and berate someone for asking
a simple question, without actually giving him a straight answer.
Now I remember why I unsubscribed from this group before...
L
listrecv
Thanks for the support Neil.
G
gabriele renzi
(e-mail address removed) ha scritto:
probably the only chance is using jruby, but are you sure you can't do
what you want with Og ?
probably the only chance is using jruby, but are you sure you can't do
what you want with Og ?
W
Wilson Bilkovich
I won't claim to support this idea. Personally, I think it's like
having your whole BMW chromed. Heh.
However, you should be able to actually do it with something like:
http://rjni.rubyforge.org/
..or:
http://raa.ruby-lang.org/project/rjb/
I'm not sure if there's a good way to gen the XDoclet tags in Ruby.=20
Presumably there's a fancy ERb trick you can use.