How about this solution

[John]

Hi,
I am also new with C.I am studying the C in course.
I performed this solution just as Practice to me.
I found this Problem among messages from this page on Dec.27.
The Problem says:

Declare an array a[10], insert the first element of the array into the
position specified by a following integer and print the contents.
output Example:
1 2 3 4 5 6 7 8 9 10
4
2 3 4 1 5 6 7 8 9 10

I tried .the result showed the error in output and it print the
different output and not the same as said.
then what would be the best way to do that?what is the most proper
alternative way to pay for this problem?
Thanks for all.

My Proposed solution is as follows:

#include <stdio.h>

int main ()
{
int a[10], x;
int i;


for(i=0; i<10; i++){
scanf(" %d", &a);
}

putchar('\n');
for(i=0; i<10; i++){
printf("%d ",a);
}
putchar('\n');


x = a[0];a[0]= a[1]; a[1]=a[2];
a[2]=a[3];a[3]=x;

for(i=0; i<10; i++){
printf("%d ",a);
}
putchar('\n');
return 0;
}

 

[Jon Yi \(???\)]

Declare an array a[10], insert the first element of the array into the

position specified by a following integer and print the contents.
output Example:
1 2 3 4 5 6 7 8 9 10
4
2 3 4 1 5 6 7 8 9 10

I tried .the result showed the error in output and it print the
different output and not the same as said.
then what would be the best way to do that?what is the most proper
alternative way to pay for this problem?

Cash in an envelop is the best. I will take Paypal. The amount is up to you.

for(i=0; i<10; i++){
scanf(" %d", &a); --- for testing, just do a = i;
}
x = a[0];a[0]= a[1]; a[1]=a[2];
a[2]=a[3];a[3]=x; ---- > assuming the input was 4 is not good. Get it from

the user, then use a loop to copy. Flexibility is what you want.
Here is my version that seems to do what you want.
#include <stdio.h>

int main ()
{
int a[10], x, temp;
int i;
for(i=0; i<10; i++){
a = i;
printf("%d ",a);
}

printf("\nEnter a number:");
scanf("%d", &x);
if(x>=10) return 1;
temp = a[0];
for (i=0;i<x;i++)
a = a[i+1];
a[x-1] = temp;

for(i=0; i<10; i++)
printf("%d ",a);
printf("\n");
return 0;
}

 

[John]

Thanks Jon Yi,
But I was asked on starting from 1 and not zero.
as you put:
int i;
for(i=0; i<10; i++){
a = i;
printf("%d ",a);

it bring the output from 0 to 9.
now,I am asking if i put like this:

a=i +1

then,the out put will show:
1 2 3 4 5 6 7 8 9 10
what do you think about?Is it a correct way or no?

Cheers!
John

}

 

[Lawrence Kirby]

Thanks Jon Yi,
But I was asked on starting from 1 and not zero.
as you put:
int i;
for(i=0; i<10; i++){
a = i;
printf("%d ",a);

it bring the output from 0 to 9.
now,I am asking if i put like this:

a=i +1

then,the out put will show:
1 2 3 4 5 6 7 8 9 10
what do you think about?Is it a correct way or no?

Yes, that's fine. If you need to read the numbers in you can still do it
as you did originally.

Lawrence