How can I read from the entire standard input at once?

[Chad]

The following code is a stripped down version of a large project. The
question is why do I have to press ctrl z every time to get the
output? That is, say I type the following at the command line

1 - 3

and then press the enter key on my keyboard. I press ctrl z and I get
'The value is 1' . Then I press it again, I get a 'The value is '.
Then I press it again, I get 'The value is -', etc. Ideas on how to
get how get the entire output out at once? Ideally what I would like
to do is when I type in the above, press the enter key, then, after I
press ctrl z, get

The value is 1
The value is
found the minus sign
The value is 3


import java.util.Scanner;

public class hack {

public static int getNextNumber(String [] storeValues) {
String value = null;
int i = 0;
Scanner input = new Scanner(System.in);

while(input.hasNextLine()) {

try {
storeValues[i++] = input.nextLine();
} catch (IllegalStateException e) {
return -1; //EOF
}
}

return 0;
}

public static void main(String[] args) {
String[] values = new String[100];

char[] getNumber;
int value;
int i = 0;
while ( ( value = getNextNumber(values) ) != -1) {
getNumber = values[0].toCharArray();
switch (value) {
case 0: {
System.out.println("The value is " + getNumber);
i++;
break;
}
case '+': {
System.out.println("found plus sign");
i++;
break;
}
case '-': {
System.out.println("found minus sign");
i++;
break;
}
case '*': {
System.out.println("found mult sign");
i++;
break;
}
case '/': {
System.out.println("found division sign");
i++;
break;
}
default: break;
}
}//end while

}//end main()

 

[Eric Sosman]

The following code is a stripped down version of a large project. The
question is why do I have to press ctrl z every time to get the
output? That is, say I type the following at the command line

1 - 3

and then press the enter key on my keyboard. I press ctrl z and I get
'The value is 1' . Then I press it again, I get a 'The value is '.
Then I press it again, I get 'The value is -', etc. Ideas on how to
get how get the entire output out at once? Ideally what I would like
to do is when I type in the above, press the enter key, then, after I
press ctrl z, get

The value is 1
The value is
found the minus sign
The value is 3

Is this a serious question, or are you trolling? Benefit of
the doubt ...

import java.util.Scanner;

public class hack {

public static int getNextNumber(String [] storeValues) {
String value = null;
int i = 0;
Scanner input = new Scanner(System.in);

while(input.hasNextLine()) {

try {
storeValues[i++] = input.nextLine();
} catch (IllegalStateException e) {
return -1; //EOF
}
}

return 0;
}

A few observations about this method. First, every time it's
called it creates a brand-new Scanner reading System.in. If you
call it twelve times you've got twelve Scanners all fighting
over the same input source. I'm too revolted by the idea to spend
time figuring out how the Scanners resolve their squabbles; it's
like asking whether the tapeworms are more likely to exit the
terminus of your gut head- or tail-first. I prefer not to know.

Second, and take note of this in relation to the subsequent
switch statement, this method returns either 0 or -1. Nothing else,
not ever.

Third, the getNextNumber name is not at all descriptive of what
the method does. You might as well have called it getLost.

public static void main(String[] args) {
String[] values = new String[100];

char[] getNumber;
int value;
int i = 0;
while ( ( value = getNextNumber(values) ) != -1) {

Since the method returns either 0 or -1, we know that if the
program reaches this point we have `value' equal to 0.

getNumber = values[0].toCharArray();

Why? Have you never heard of String's charAt method?

switch (value) {
case 0: {
System.out.println("The value is " + getNumber);
i++;
break;

The switch statement selects this case every time. The first time
around, it prints the first character (if there is one) of the first
String (if there is one) read by the first Scanner, and ignores all the
rest of the first String and any additional Strings the Scanner may
have produced. The second time, it prints the second character (if there
is one) of the first String (if there is one) read by the second Scanner
(if it's able to read at all), ignoring all the rest of the input. The
third time it outputs the third character of the third Scanner's first
String, then the fourth time, ...

}

Since `value' is zero, the remainder of the switch is irrelevant:
None of it can ever be executed.

case '+': {
System.out.println("found plus sign");
i++;
break;
}
case '-': {
System.out.println("found minus sign");
i++;
break;
}
case '*': {
System.out.println("found mult sign");
i++;
break;
}
case '/': {
System.out.println("found division sign");
i++;
break;
}
default: break;
}
}//end while

}//end main()

The more I think about it, the more I think giving you the benefit
of the doubt may have been foolhardy. Eleven to two you're trolling.

 

[Roedy Green]

or are you trolling?

what made you suspect that?
--
Roedy Green Canadian Mind Products
http://mindprod.com
It should not be considered an error when the user starts something
already started or stops something already stopped. This applies
to browsers, services, editors... It is inexcusable to
punish the user by requiring some elaborate sequence to atone,
e.g. open the task editor, find and kill some processes.

 

[Eric Sosman]

what made you suspect that?

"Chad" has been around on this and other forums for several
years. If s/he has that much experience with programming -- even if
all s/he's done is Turtle Graphics -- the depth of incomprehension
evidenced by the offered code is beyond my ability to accept at face
value.

Of course, it might be a new "Chad." Hence the benefit of the
doubt, and the answer pointing out (some of) the problems.

 

[Chad]

     "Chad" has been around on this and other forums for several
years.  If s/he has that much experience with programming -- even if
all s/he's done is Turtle Graphics -- the depth of incomprehension
evidenced by the offered code is beyond my ability to accept at face
value.

     Of course, it might be a new "Chad."  Hence the benefit of the
doubt, and the answer pointing out (some of) the problems.

Eric beat me to the explanation. But there is a little bit more to the
story. Over the years both me and Eric have gone back on forth on
comp.lang.c, comp.unix.programmer, and a few other places. Anyways,
I've gone on record several times as saying that I'm "bit slow". In
real life I'm just some seasonal blue collar factory worker. Usually I
just sit around the house and drink after they lay me off for the
season.

However, maybe like a year ago, I started to take some programming
classes at the local extension. It was either that, or spend another
year drinking myself sober. Now the question I posted in here is
actually part of a school project.

Chad