how to break tuple to separate variables

[Stano Paska]

Hi.

I need pass variables to function like tuple, but function accepts
separate variables.

Is there some elegant solution?

My example:

# -------------------------------
import datetime

def date2tuple(aaa):
try:
y = int(aaa[:4])
m = int(aaa[5:7])
d = int(aaa[8:10])
except:
y = m = d = 0
return (y, m, d)

# i need some like this
bbb = datetime.date(date2tuple('2004-11-03'))

# but date requires
bbb = datetime.date(2004, 11, 03)

# -------------------------------

Thanks.

Stano Paska

 

[Paul Rubin]

# i need some like this
bbb = datetime.date(date2tuple('2004-11-03'))

# but date requires
bbb = datetime.date(2004, 11, 03)

use:

bbb = datetime.date(*date2tuple('2004-11-03'))

the '*' before the arg means convert the tuple to an arg list.

 

[Larry Bates]

Take a look at the built-in apply function:

apply(datetime.date, date2tuple('2004-11-03'))

Larry Bates
Syscon, Inc.

 

[Peter Abel]

Hi.

I need pass variables to function like tuple, but function accepts
separate variables.

Is there some elegant solution?

My example:

# -------------------------------
import datetime

def date2tuple(aaa):
try:
y = int(aaa[:4])
m = int(aaa[5:7])
d = int(aaa[8:10])
except:
y = m = d = 0
return (y, m, d)

# i need some like this
bbb = datetime.date(date2tuple('2004-11-03'))

# but date requires
bbb = datetime.date(2004, 11, 03)

# -------------------------------

Thanks.

Stano Paska

try:

Regards
Peter

 

[Peter Abel]

Hi.

I need pass variables to function like tuple, but function accepts
separate variables.

Is there some elegant solution?

My example:

# -------------------------------
import datetime

def date2tuple(aaa):
try:
y = int(aaa[:4])
m = int(aaa[5:7])
d = int(aaa[8:10])
except:
y = m = d = 0
return (y, m, d)

# i need some like this
bbb = datetime.date(date2tuple('2004-11-03'))

# but date requires
bbb = datetime.date(2004, 11, 03)

# -------------------------------

Thanks.

Stano Paska

Sorry, I didn't read your post seriously enough.[2004, 11, 3]

bbb = datetime.date(*map(int,'2004-11-03'.split('-')))
as Paul Rubin pointed out.

Regards
Peter