How to do this in XSLT

[Sandy]

Hi,

I have following XML. I want to write an XSL file which can take the first
and second <NAME> elements and put them in the output (which is a csv file
as shown below).
But i am not able to find how to do this using XSLT transformations.

Any help is greatly appreciated.

Input XML file
<?xml version="1.0"?>
<?xml-stylesheet type="text/xml" href="test.xsl"?>
<LIST>
<NAME>
<FIRST>first1</FIRST>
<LAST>last1</LAST>
</NAME>
<NAME>
<FIRST>first2</FIRST>
<LAST>last2</LAST>
</NAME>
<NAME>
<FIRST>first3</FIRST>
<LAST>last3</LAST>
</NAME>
<NAME>
<FIRST>first4</FIRST>
<LAST>last4</LAST>
</NAME>
................
..................... (n number of NAME's)
</LIST>

*****************************************************************
Output

first1,Last1
first2,last2

 

[JAPISoft]

Hi Sandy,

Here a sample, please use an editor for checking the syntax, it is
written without one :

....

<xslutput method="text"/>

<xsl:template match="LIST">
<xsl:apply-templates select="NAME"/>
</xsl:template>

<xsl:template match="NAME">
<xsl:value-of select="FIRST"/>,<xsl:value-of select="LAST"/>
</xsl:template>

Best regards,

A.Brillant
Editix - XML Editor and XSLT Debugger
http://www.editix.com

 

[Matt Sannes]

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xslutput method="text" />
<xsl:template match="*">
<apply-templates/>
</xsl:template>

<xsl:template match="LIST">
<xsl:for-each select="NAME">
<xsl:value-of select="FIRST"/>,<xsl:value-of
select="LAST"/><xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

Matthew Sannes
Docsoft .NET Developer

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