How to instantiate template when it is arguments satisfy some condition?

[PengYu.UT]

For example, I want the return_type of the two arguments of Expr2 be
the same. Otherwise, the compilor should give an error.

Would you please tell me how to do that?

Thanks,
Peng


template <typename T>
struct Expr1{
typedef T return_type;
};

template <typename E, typename T>
struct Expr2;

template <typename E1, typename E2>
struct Expr2 {//I want E1 and E2's return_type be the same.
typedef typename E1::return_type return_type;
};

int main(int argc, char *argv[]){
Expr2<Expr1<int>, Expr1<double> > a;
}

 

[Alf P. Steinbach]

* (e-mail address removed):

For example, I want the return_type of the two arguments of Expr2 be
the same. Otherwise, the compilor should give an error.

Would you please tell me how to do that?

template< typename A, typename B >
struct IsSameType{ enum{ yes=false }; };

template< typename T >

template <typename T>
struct Expr1{
typedef T return_type;
};

template <typename E, typename T>
struct Expr2;

template <typename E1, typename E2>
struct Expr2 {//I want E1 and E2's return_type be the same.
typedef typename E1::return_type return_type;
BOOST_STATIC_ASSERT((

};

int main(int argc, char *argv[]){
Expr2<Expr1<int>, Expr1<double> > a;
}

 

[Tao Wang]

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For example, I want the return_type of the two arguments of Expr2 be
the same. Otherwise, the compilor should give an error.

Would you please tell me how to do that?

Thanks,
Peng


template <typename T>
struct Expr1{
typedef T return_type;
};

template <typename E, typename T>
struct Expr2;

template <typename E1, typename E2>
struct Expr2 {//I want E1 and E2's return_type be the same.
typedef typename E1::return_type return_type;
};

int main(int argc, char *argv[]){
Expr2<Expr1<int>, Expr1<double> > a;
}

To avoid the problem, why don't use one type, if two type are actually same?

template <typename T>
struct Expr1{
typedef T return_type;
};

template <typename E>
struct Expr2 {
typedef typename E::return_type return_type;
};

int main(int argc, char *argv[]){
Expr2<Expr1<int> > a;
return 0;
}
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Comment: Using GnuPG with Fedora - http://enigmail.mozdev.org

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[PengYu.UT]

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Hash: SHA1

For example, I want the return_type of the two arguments of Expr2 be
the same. Otherwise, the compilor should give an error.

Would you please tell me how to do that?

Thanks,
Peng


template <typename T>
struct Expr1{
typedef T return_type;
};

template <typename E, typename T>
struct Expr2;

template <typename E1, typename E2>
struct Expr2 {//I want E1 and E2's return_type be the same.
typedef typename E1::return_type return_type;
};

int main(int argc, char *argv[]){
Expr2<Expr1<int>, Expr1<double> > a;
}

To avoid the problem, why don't use one type, if two type are actually same?

template <typename T>
struct Expr1{
typedef T return_type;
};

template <typename E>
struct Expr2 {
typedef typename E::return_type return_type;
};

int main(int argc, char *argv[]){
Expr2<Expr1<int> > a;
return 0;
}

Because I might have Expr3 which can be used as the template arguments
of Expr2.

template <typename T>
struct Expr3{
typedef std::complex<T> return_type;
};

 

[PengYu.UT]

* (e-mail address removed):

For example, I want the return_type of the two arguments of Expr2 be
the same. Otherwise, the compilor should give an error.

Would you please tell me how to do that?

template< typename A, typename B >
struct IsSameType{ enum{ yes=false }; };

template< typename T >

template <typename T>
struct Expr1{
typedef T return_type;
};

template <typename E, typename T>
struct Expr2;

template <typename E1, typename E2>
struct Expr2 {//I want E1 and E2's return_type be the same.
typedef typename E1::return_type return_type;
BOOST_STATIC_ASSERT((

};

int main(int argc, char *argv[]){
Expr2<Expr1<int>, Expr1<double> > a;
}

Do you know how BOOST_STATIC_ASSERT is implemented? I might not be able
to use boost.

Thanks,
Peng

 

[Thomas Tutone]

Do you know how BOOST_STATIC_ASSERT is implemented?

Yes.

Why don't you look at the source code for yourself? You can download
it and use it, subject to Boost's license.

http://www.boost.org/boost/static_assert.hpp

You can also find a similar static assert macro in Modern C++ Design.

Best regards,

Tom

 

[John Carson]

For example, I want the return_type of the two arguments of Expr2 be
the same. Otherwise, the compilor should give an error.

Would you please tell me how to do that?

Thanks,
Peng


template <typename T>
struct Expr1{
typedef T return_type;
};

template <typename E, typename T>
struct Expr2;

template <typename E1, typename E2>
struct Expr2 {//I want E1 and E2's return_type be the same.
typedef typename E1::return_type return_type;
};

int main(int argc, char *argv[]){
Expr2<Expr1<int>, Expr1<double> > a;
}

template <typename T>
struct Expr1
{
typedef T return_type;
};

// forward declare only
template<class A, class B>
class EqualTypes;

// specialize for A == B
template<class A>
class EqualTypes<A,A>
{};

template <typename E1, typename E2>
struct Expr2
{
EqualTypes<typename E1::return_type, typename E2::return_type> eq;
};

int main()
{
Expr2<Expr1<int>, Expr1<double> > a;
}