how to make a[2][2][3]=4 work?

[gz zz]

a=Hash.new{|h,k|
h[k]={}
}

p a[1]=1

a[2][1]=2
#a[2][2][3]=4
p a

 

[gz zz]

I know this can work,but I think it is suck
a=Hash.new{|h,k|
h[k]=Hash.new{|h,k|h[k]=Hash.new{|h,k|h[k]={}}}
}

p a[1]=1

a[2][1]=2
a[2][2][3]=4
a[3][1][1][1]=1
p a

 

[Daniel Sheppard]

I know this can work,but I think it is suck

a=3DHash.new{|h,k|
h[k]=3DHash.new{|h,k|h[k]=3DHash.new{|h,k|h[k]=3D{}}}
}
=20
p a[1]=3D1
=20
a[2][1]=3D2
a[2][2][3]=3D4
a[3][1][1][1]=3D1
p a

build_hash =3D proc {|h,k|h[k] =3D Hash.new &build_hash }
a =3D Hash.new &build_hash=20

 

[Sylvain Joyeux]

def recursive_hash
Hash.new { |h, k| h[k] = recursive_hash }
end
a = recursive_hash

Or even

class Hash
def self.recursive
new { |h, k| h[k] = recursive }
end
end

which gives

a = Hash.recursive =>
a[1][2][3][4] = 1 => 1
puts a.inspect

{1=>{2=>{3=>{4=>1}}}}

 

[Daniel Martin]

In addition to what's already been posted, there's this, which doesn't
require any extra variables or methods:

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

a[2][1]=2
a[2][2][3]=4
a[3][1][1][1]=1
p a

irb(main):001:0> a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}
=> {}
irb(main):002:0> a[2][1]=2
=> 2
irb(main):003:0> a[2][2][3]=4
=> 4
irb(main):004:0> a[3][1][1][1]=1
=> 1
irb(main):005:0> p a
{2=>{1=>2, 2=>{3=>4}}, 3=>{1=>{1=>{1=>1}}}}
=> nil

 

[Jenda Krynicky]

a=Hash.new{|h,k|
h[k]={}
}

p a[1]=1

a[2][1]=2
#a[2][2][3]=4
p a

Sure. Use Perl.

Oops, sorry. I forgot, datastructure autovivification is wrong,
variables springing into life (or maybe not, read the rest of the method
to find out) inadvertently are good.

Jenda

 

[Martin DeMello]

Sure. Use Perl.

Oops, sorry. I forgot, datastructure autovivification is wrong,
variables springing into life (or maybe not, read the rest of the method
to find out) inadvertently are good.

That's okay, it happens to the best of us.

martin

 

[Phrogz]

In addition to what's already been posted, there's this, which doesn't
require any extra variables or methods:

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

Thanks for this - I didn't know about the default_proc method. Quite
elegant in this case.

 

[Fsormok Fsormok]

Sure. Use Perl.

What's the ruby-way of such things?

e.g.:

int[eth0][ip] = "10.0.0.1"
int[eth0][mask] = "255.255.255.0"
int[eth0][cidr] = "24"
int[eth1][ip] = "10.0.1.1"
int[eth1][mask] = "255.255.255.0"
int[eth1][cidr] = "24"

 

[Bill Kelly]

Sure. Use Perl.

What's the ruby-way of such things?

e.g.:

int[eth0][ip] = "10.0.0.1"
int[eth0][mask] = "255.255.255.0"
int[eth0][cidr] = "24"
int[eth1][ip] = "10.0.1.1"
int[eth1][mask] = "255.255.255.0"
int[eth1][cidr] = "24"
.
.
.

I like it if I have all these informations handy within one hash. But
even for me as a realy ruby-newby this looks much more like perl than
ruby.

It would be great to hear your thoughts how this would be done "the ruby
way"...

clean and elegant

You can do that in Ruby, if you want to.
See: http://blade.nagaokaut.ac.jp/cgi-bin/scat.rb/ruby/ruby-talk/255313

irb(main):011:0> int = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}
=> {}
irb(main):012:0> int[:eth0][:ip] = "10.0.0.1"
irb(main):013:0> int[:eth0][:mask] = "255.255.255.0"
irb(main):014:0> int[:eth0][:cidr] = "24"
irb(main):015:0> int[:eth1][:ip] = "10.0.1.1"
irb(main):016:0> int[:eth1][:mask] = "255.255.255.0"
irb(main):017:0> int[:eth1][:cidr] = "24"
irb(main):018:0> int
=> {:eth0=>{:ip=>"10.0.0.1", :mask=>"255.255.255.0", :cidr=>"24"}, :eth1=>{:ip=>"10.0.1.1", :mask=>"255.255.255.0", :cidr=>"24"}}


Another possibility might be OpenStruct.

irb(main):026:0> require 'ostruct'
=> true
irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}
=> {}
irb(main):028:0> int[:eth0].ip = "10.0.0.1"
irb(main):029:0> int[:eth0].mask = "255.255.255.0"
irb(main):030:0> int[:eth0].cidr = "24"
irb(main):031:0> int[:eth1].ip = "10.0.1.1"
irb(main):032:0> int[:eth1].mask = "255.255.255.0"
irb(main):033:0> int[:eth1].cidr = "24"
irb(main):034:0> int
=> {:eth0=>#<OpenStruct ip="10.0.0.1", mask="255.255.255.0", cidr="24">, :eth1=>#<OpenStruct ip="10.0.1.1", mask="255.255.255.0",
cidr="24">}


Regards,

Bill

 

[William James]

a=Hash.new{|h,k|
h[k]={}

}

p a[1]=1

a[2][1]=2
#a[2][2][3]=4

a = {}
==>{}
a[1] = 1
==>1
a[ [2,1] ] = 2
==>2
a[ [2,2,3] ] = 4
==>4
p a
{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
==>nil

 

[Fsormok Fsormok]

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

irb(main):026:0> require 'ostruct'
irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}

a = {}
==>{}
a[1] = 1
==>1
a[ [2,1] ] = 2
==>2
a[ [2,2,3] ] = 4
==>4
p a
{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
==>nil

Tanks for the replies.

I'm just a little bit confused because in ruby everything is lean and
clean but when it comes to hashes of hashes it gets kind of complicated.
For me it looks like ruby has another "concept" of solving such things.

-fsormok

 

[Robert Dober]

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

irb(main):026:0> require 'ostruct'
irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}

a = {}
==>{}
a[1] = 1
==>1
a[ [2,1] ] = 2
==>2
a[ [2,2,3] ] = 4
==>4
p a
{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
==>nil

Tanks for the replies.

I'm just a little bit confused because in ruby everything is lean and
clean but when it comes to hashes of hashes it gets kind of complicated.
For me it looks like ruby has another "concept" of solving such things.

Hmm the context of this statement seems not complete in *this* thread,
maybe you could elaborate on this a little bit?
Personally I feel that Ruby's concept of Hashes is clearcut and
exactly the same as in most of its relatives (Perl,Python...).

What exactly would you like to have "simpler"?

Cheers
Robert

 

[Mark Thomas]

Sure. Use Perl.

What's the ruby-way of such things?

e.g.:

int[eth0][ip] = "10.0.0.1"
int[eth0][mask] = "255.255.255.0"
int[eth0][cidr] = "24"
int[eth1][ip] = "10.0.1.1"
int[eth1][mask] = "255.255.255.0"
int[eth1][cidr] = "24"
.
.
.

I like it if I have all these informations handy within one hash. But
even for me as a realy ruby-newby this looks much more like perl than
ruby.

It would be great to hear your thoughts how this would be done "the ruby
way"...

clean and elegant

In my personal opinion, multilevel hashes aren't clean and elegant in
any language. I'd try to make an object out of it:

class Interface
attr_accessor :name, :ip, :mask, :cidr
end

i = Interface.new
i.name = "eth0"
i.ip = "10.0.0.1"
i.mask = "255.255.255.0"
i.cidr = 24

- Mark.

 

[Fsormok Fsormok]

Thanx Mark

This is exactly what i liked to hear

In my personal opinion, multilevel hashes aren't clean and elegant in
any language.

HoH are quiet common in perl (at least I use them alot), not in Ruby
IMHO.

But as always: TMTOWTDI

 

[Robert Klemme]

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

irb(main):026:0> require 'ostruct'
irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}

a = {}
==>{}
a[1] = 1
==>1
a[ [2,1] ] = 2
==>2
a[ [2,2,3] ] = 4
==>4
p a
{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
==>nil

Tanks for the replies.

I'm just a little bit confused because in ruby everything is lean and
clean but when it comes to hashes of hashes it gets kind of complicated.
For me it looks like ruby has another "concept" of solving such things.

Its this what you are looking for?

$ ruby <<XXX

miss = lambda {|h,k| h[k] = Hash.new(&miss)}
hash = Hash.new(&miss)
hash[1][2]=3
hash[4]=5
p hash
XXX

{1=>{2=>3}, 4=>5}

Kind regards

robert

 

[Gabe Da silveira]

In addition to what's already been posted, there's this, which doesn't
require any extra variables or methods:

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

That's clever, but I think the way it automatically creates keys is
wrong. You need to be able to check to see if a key exists without
polluting the hash with a bunch of empties.

Hence my new gem:

http://github.com/dasil003/safe-nested-hash