How to return a pointer to an array?

[mani]

int (*nVar)[10]..This is the variable i used in a function.. i
tried ...nothing worked.. anyone please tell me how to return it....

 

[Pranav]

int (*nVar)[10]..This is the variable i used in a function.. i
tried ...nothing worked.. anyone please tell me how to return it....

Just return nVar.....,

 

[Salt_Peter]

int (*nVar)[10]..This is the variable i used in a function.. i
tried ...nothing worked.. anyone please tell me how to return it....

Show minimum, compileable code please.
We don't know if what you have is a local array and a dangling
pointer.
Prefer const references. Prefer std::vector<> over fixed arrays.

#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>

template< typename T >
void foo( const std::vector< T >& r_v )
{
std::copy( r_v.begin(),
r_v.end(),
std:stream_iterator< T >(std::cout, " ") );
std::cout << std::endl;
}

int main()
{
std::vector< int > vn(10, 99);
foo( vn );
}

/*
99 99 99 99 99 99 99 99 99 99
*/

The above should really be an operator<<
If you prefer working with dumb fixed arrays:

template< typename T, const std::size_t Size >
void bar( const T (& r_a)[ Size ] )
{
for( std::size_t i = 0; i < Size; ++i)
{
std::cout << r_a;
std::cout << " ";
}
std::cout << std::endl;
}

int main()
{
int array[10] = { 0 };
bar( array );
}

/*
0 0 0 0 0 0 0 0 0 0
*/