How #{} works

[François Montel]

Can anyone explain this?

a = ["b"] => ["b"]
a == "b" => false
"#{a}" == "b"

=> true

Since a is an array, how come the last statement evaluates as true?

 

[Sebastian Hungerecker]

a =3D ["b"]

=3D> ["b"]

=3D> false

=3D> true

Since a is an array, how come the last statement evaluates as true?

"#{ ["b"] }" =3D=3D ["b"].to_s #=3D> true
["b"].to_s =3D=3D "b" #=3D> true
["b"].to_s #=3D> "b"

 

[Leo]

"#{a}" == "b"

=> true

Since a is an array, how come the last statement evaluates as true?

You could try ruby 1.9, if you prefer false:

a = ["b"] => ["b"]
"#{a}" == "b" => false
"#{a}" => "[\"b\"]"
["b"].to_s

=> "[\"b\"]"

 

[Paganoni]

le 22/03/2009 14:53, François Montel nous a dit:

Can anyone explain this?

a = ["b"] => ["b"]
a == "b" => false
"#{a}" == "b"

=> true

Since a is an array, how come the last statement evaluates as true?

Because, since it's embedded in a string Ruby does a .to_s against the
array. And ["b"].to_s == "b" is true