ij = ic: 0;

[Chris Saunders]

I was reading some C code and came across this:

ij = ic: 0;

ij and ic are of type int.

I assume that ij and ic are being assigned the value 0 but
I don't recall ever seeing this before.

Anyone know if this is proper?

Regards
Chris Saunders

 

[Krishanu Debnath]

I was reading some C code and came across this:

ij = ic: 0;

ij and ic are of type int.

I assume that ij and ic are being assigned the value 0 but
I don't recall ever seeing this before.

Anyone know if this is proper?

Regards
Chris Saunders

No, It is not. Did you mean ','/'=' instead of ':' ?

krishanu@meghna[86] cat nonsense.cxx
#include<stdio.h>

int main()
{
int ij = 0;
int ic = 0;
ij = ic: 0;
return 0;
}
krishanu@meghna[87] mc nonsense.cxx
nonsense.cxx: In function `int main()':
nonsense.cxx:7: parse error before `:' token
krishanu@meghna[88]


Krishanu

 

[Keith Thompson]

I was reading some C code and came across this:

ij = ic: 0;

ij and ic are of type int.

I assume that ij and ic are being assigned the value 0 but
I don't recall ever seeing this before.

No, you weren't reading some C code. }

What context did it appear in (just a few lines)? Are you sure that
was exactly what it said? If the ':' were a ';', it would be legal
(but not necessarily sensible).

 

[Allan Bruce]

No, you weren't reading some C code. }

What context did it appear in (just a few lines)? Are you sure that
was exactly what it said? If the ':' were a ';', it would be legal
(but not necessarily sensible).

or if it were
ij = ic? 5 : 0;
or similar, it would be valid

 

[Richard Tobin]

ij = ic: 0;

This is not syntactically correct. Is it perhaps part of some larger
conditional expression (that is, a use of the ternary a?b:c operator)?

-- Richard