F
frustratedcoder
When I call the transformnode on my xml object like this:
response.write xmlobj.transformnode(xsl) I get the actual xsl sent to
the browser.
Here is my code:
<%@LANGUAGE="VBSCRIPT"%>
<%
Dim xmlhttp, xsldoc, xmldoc
set xmlhttp = Server.CreateObject("Microsoft.XMLHTTP")
xmlhttp.open "GET", "http://some-server.com/xmlfile", false
xmlhttp.send
set xsldoc = Server.CreateObject("Microsoft.XMLDOM")
xsldoc.async = false
xsldoc.load(Server.MapPath("stylesheet.xsl"))
set xmldoc = Server.CreateObject("Microsoft.XMLDOM")
xmldoc.async = false
xmldoc.loadXML(xmlhttp.responseText)
response.write xmldoc.transformNode(xsldoc)
%>
No error message is sent back from the object, I just get the xsl if I
view the source.
I have tried to call a newer xml object but this appears to be the only
accessible to me on the server.
response.write xmlobj.transformnode(xsl) I get the actual xsl sent to
the browser.
Here is my code:
<%@LANGUAGE="VBSCRIPT"%>
<%
Dim xmlhttp, xsldoc, xmldoc
set xmlhttp = Server.CreateObject("Microsoft.XMLHTTP")
xmlhttp.open "GET", "http://some-server.com/xmlfile", false
xmlhttp.send
set xsldoc = Server.CreateObject("Microsoft.XMLDOM")
xsldoc.async = false
xsldoc.load(Server.MapPath("stylesheet.xsl"))
set xmldoc = Server.CreateObject("Microsoft.XMLDOM")
xmldoc.async = false
xmldoc.loadXML(xmlhttp.responseText)
response.write xmldoc.transformNode(xsldoc)
%>
No error message is sent back from the object, I just get the xsl if I
view the source.
I have tried to call a newer xml object but this appears to be the only
accessible to me on the server.