berklee just berklee said:
I want to run a code module by loading the code as any other text file, and
then calling exec() on its contents.
For some reason, Python doesn't seem to find the includes that are
referenced in the script being called.
I tried dropping it into the Python 'lib' folder, and in the same folder as
my script, neither seems to work?
Any suggestions?
Here is some code that I use:
# class for compiling and using python code (Text)
class PyCode:
def __init__(self):
self.code = None
self.module = None
# compile module from file
def fromFile(self, filename):
f = open(filename, 'r')
text = f.read()
f.close()
return self.CompileModule(GetFilenameBase(filename), text)
# compile to a module (with name moduleName) from text (code)
def CompileModule(self,moduleName, text):
# remove all cariage returns (compile does not like it)
text = string.replace(text, '\r', '')
# make sure there is a line feed at the end
# compile does not like it if there is not
if text and text[-1] != '\n':
text += '\n'
co = compile(text, '', 'exec')
# create a new module and exec the code object into the dict
import imp
codeModule = imp.new_module(moduleName)
exec co in codeModule.__dict__
return codeModule
# clear the compiled code
def SetCode(self, code, bCheckDiff = 1):
code = string.strip(code)
if (bCheckDiff and code != self.code) or not bCheckDiff:
self.code = code
if self.code:
self.module = self.CompileModule('CodeEdit', self.code)
else:
self.module = None
# exec code in the module
def execCode(self, code_str):
exec code_str in self.module.__dict__
********************************************************
to Use:
pc = PyCode()
module = pc.fromFile('Test.py')
# now module should act as any other module object
Hope this Helps,
Brent
