Indenting strings - elegant alternatives?

[Ronald Fischer]

Just in case someone would like to contribute ideas of elegant code:

PROBLEM:

Given a string of lines (for example, "abc\nde\nfgh\n") and a number n,=20
produce a string of the same lines, but each line indented by n spaces.
If the original string does NOT end in \n, it is OK (but not required)
to have it ending in \n in the result.

Speed is not an issue; I'm mainly looking EITHER for compact/elegant=20
code in Core Ruby (noing well that elegance is a very subjective=20
criterium), OR for some library function which already has solved this.

Here is my own (pretty straightforward) solution to the problem:

def indent(n,s)
(s.split.map {|x| (' '*n)+x}.join("\n"))+"\n"
end

This works, so the only reason I'm posting this, is to learn about
alternative ways of doing this.

Ronald
--=20
Ronald Fischer <[email protected]>
Phone: +49-89-452133-162

 

[Daniel Lucraft]

Given a string of lines (for example, "abc\nde\nfgh\n") and a number n,
produce a string of the same lines, but each line indented by n spaces.

This would be my first inclination:
" "*n + s.gsub("\n", "\n"+" "*n)

BTW, I don't think yours handles "abc\n\ndef" as you might hope...

best,
Dan

 

[Xavier Noria]

Just in case someone would like to contribute ideas of elegant code:

PROBLEM:

Given a string of lines (for example, "abc\nde\nfgh\n") and a
number n,
produce a string of the same lines, but each line indented by n
spaces.
If the original string does NOT end in \n, it is OK (but not required)
to have it ending in \n in the result.

Speed is not an issue; I'm mainly looking EITHER for compact/elegant
code in Core Ruby (noing well that elegance is a very subjective
criterium), OR for some library function which already has solved
this.

Here is my own (pretty straightforward) solution to the problem:

def indent(n,s)
(s.split.map {|x| (' '*n)+x}.join("\n"))+"\n"
end

Another solution is:

s.gsub(/^/, ' ' * n)

-- fxn

 

[William James]

Just in case someone would like to contribute ideas of elegant code:

PROBLEM:

Given a string of lines (for example, "abc\nde\nfgh\n") and a number n,
produce a string of the same lines, but each line indented by n spaces.
If the original string does NOT end in \n, it is OK (but not required)
to have it ending in \n in the result.

Speed is not an issue; I'm mainly looking EITHER for compact/elegant
code in Core Ruby (noing well that elegance is a very subjective
criterium), OR for some library function which already has solved this.

Here is my own (pretty straightforward) solution to the problem:

def indent(n,s)
(s.split.map {|x| (' '*n)+x}.join("\n"))+"\n"
end

This works, so the only reason I'm posting this, is to learn about
alternative ways of doing this.

def indent(n,s)
s.gsub( /^/, ' '*n )
end

 

[Ronald Fischer]

BTW, I don't think yours handles "abc\n\ndef" as you might hope...

Indeed! Thank you for pointing this out!

Ronald

 

[Bertram Scharpf]

Hi,

Am Mittwoch, 19. Sep 2007, 20:46:30 +0900 schrieb Xavier Noria:

Another solution is:

s.gsub(/^/, ' ' * n)

Or even

s.gsub /^(?!$)/, " "*n

Bertram

 

[Federico Zagarzazú]

something like this?
str.gsub(/\b(\w+)/) {|word| ' '*n + word}

 

[Bertram Scharpf]

Hi,

Am Donnerstag, 20. Sep 2007, 14:15:11 +0900 schrieb Federico Zagarzaz=FA:

something like this?
str.gsub(/\b(\w+)/) {|word| ' '*n + word}

/\b/ always matches before and after /\w+/.

Bertram


--=20
Bertram Scharpf
Stuttgart, Deutschland/Germany
http://www.bertram-scharpf.de