Input Error issues - Windows 7

[bryan.kardisco]

I'm new to python and am trying to just get some basic stuff up and going.

I have a very basic module called foo

It's in the following directory on my machine

C:\workspace\PyFoo\src\foo
In that folder is __init__.py (created automatically) and foo.py

foo.py looks like this

class foo():
def __init__(self, name, number):
self.name = name
self.number = number
def getName(self):
return self.name
def getNumber(self):
return self.number


If I open up command prompt and do following it works:

C:\workspace\PyFoo\src\foo>python
Python 3.3.3 (v3.3.3:c3896275c0f6, Nov 18 2013, 21:18:40) [MSC v.1600 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.

However, if I run this from C:\ I get the following

C:\>python
Python 3.3.3 (v3.3.3:c3896275c0f6, Nov 18 2013, 21:18:40) [MSC v.1600 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.Traceback (most recent call last):


I thought, well maybe it's a system error
['', 'C:\\Python33', 'C:\\Python33\\Lib', 'C:\\Python33\\DLLs', 'C:\\workspace', 'C:\\Windows\\system32\\python33.zip',
'C:\\Python33\\lib\\site-packages']
C:\>echo %PYTHONPATH%
C:\Python33;C:\Python33\Lib;C:\Python33\DLLs;C:\workspace

However, that seems OK.

Is there something I'm missing?

 

[Ned Batchelder]

I'm new to python and am trying to just get some basic stuff up and going.
Welcome!


I have a very basic module called foo

It's in the following directory on my machine

C:\workspace\PyFoo\src\foo
In that folder is __init__.py (created automatically) and foo.py

foo.py looks like this

class foo():
def __init__(self, name, number):
self.name = name
self.number = number
def getName(self):
return self.name
def getNumber(self):
return self.number


If I open up command prompt and do following it works:

C:\workspace\PyFoo\src\foo>python
Python 3.3.3 (v3.3.3:c3896275c0f6, Nov 18 2013, 21:18:40) [MSC v.1600 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.

However, if I run this from C:\ I get the following

C:\>python
Python 3.3.3 (v3.3.3:c3896275c0f6, Nov 18 2013, 21:18:40) [MSC v.1600 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.Traceback (most recent call last):


I thought, well maybe it's a system error
['', 'C:\\Python33', 'C:\\Python33\\Lib', 'C:\\Python33\\DLLs', 'C:\\workspace', 'C:\\Windows\\system32\\python33.zip',
'C:\\Python33\\lib\\site-packages']
C:\>echo %PYTHONPATH%
C:\Python33;C:\Python33\Lib;C:\Python33\DLLs;C:\workspace

However, that seems OK.

Is there something I'm missing?

The PYTHONPATH contains the directories that will be searched for
modules and packages. Your package is called foo, and is in
c:\workspace\PyFoo\src. That directory is not on the Python path, and
it isn't the current directory. Therefore, your package can't be found
and imported.

BTW: writting getters like getName and getNumber is unusual in Python.
The much more common technique is to simply use the attribute: f.name

 

[Dave Angel]

It's in the following directory on my machine

C:\workspace\PyFoo\src\foo
In that folder is __init__.py (created automatically) and foo.py

foo.py looks like this

class foo():

Ned has pointed out your path problem. But you have another,
perhaps caused by overexposure to java. You have a package, a module
and a class, all with the same name. Convention says at least
uppercase for the class. I say make every name unique till you learn
how they work.