integer to string

[james]

_itoa() is a easiest function,format is as below: you have to include
<stdlib.h>
char *_itoa( int value, char *string, int radix );

char *_i64toa( __int64 value, char *string, int radix );

char * _ui64toa( unsigned _int64 value, char *string, int radix );

wchar_t * _itow( int value, wchar_t *string, int radix );

wchar_t * _i64tow( __int64 value, wchar_t *string, int radix );

wchar_t * _ui64tow( unsigned __int64 value, wchar_t *string, int radix );

 

[AC 74]

I read from a command line using g++. I changed the argv to integers
using atoi() in order to add the numbers. Now I need to change them
from int to string and itoa is not supported. Can somebody please
help me to change these integers back to strings? Thanks.

 

[Jonathan Turkanis]

I read from a command line using g++. I changed the argv to integers
using atoi() in order to add the numbers. Now I need to change them
from int to string and itoa is not supported. Can somebody please
help me to change these integers back to strings? Thanks.

This is a famous FAQ question:
http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-38.1.

Jonathan

 

[Sumit Rajan]

I read from a command line using g++. I changed the argv to integers
using atoi() in order to add the numbers. Now I need to change them
from int to string and itoa is not supported. Can somebody please
help me to change these integers back to strings? Thanks.

Try the FAQ:

http://www.parashift.com/c++-faq-lite/misc-technical-issues.html

Regards,
Sumit.

 

[Mike Wahler]

I read from a command line using g++. I changed the argv to integers
using atoi() in order to add the numbers. Now I need to change them
from int to string and itoa is not supported. Can somebody please
help me to change these integers back to strings? Thanks.

#include <iostream>
#include <sstream>
#include <string>

int main()
{
int i(42);
std:stringstream oss;
oss << i;
std::string s(oss.str());
std::cout << s << '\n'; // prints 42
return 0;
}

-Mike

 

[Peter van Merkerk]

_itoa() is a easiest function,format is as below: you have to include
<stdlib.h>
char *_itoa( int value, char *string, int radix );

char *_i64toa( __int64 value, char *string, int radix );

char * _ui64toa( unsigned _int64 value, char *string, int radix );

wchar_t * _itow( int value, wchar_t *string, int radix );

wchar_t * _i64tow( __int64 value, wchar_t *string, int radix );

wchar_t * _ui64tow( unsigned __int64 value, wchar_t *string, int radix );

This is not a standard function (the leading underscore is a hint that it
is non-standard). Even though the library that came with your compiler has
this function, it is not defined in the C++ standard. Other implementations
of the standard library may or may not support this function.

 

[Evan Carew]

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AC,

try the Boost lib's safe cast operator:

http://www.boost.org/libs/conversion/index.html

I read from a command line using g++. I changed the argv to integers
using atoi() in order to add the numbers. Now I need to change them
from int to string and itoa is not supported. Can somebody please
help me to change these integers back to strings? Thanks.

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