mapping functions and lambda

[Suresh Jeevanandam]

Given a string
s = 'a=1,b=2'

I want to create a dictionary {'a': '1', 'b': '2'}

I did,

dict(map(lambda k: k.split('='), s.split(',')))

Is it possible to get rid of the lambda here, without having to define
another function just for this.

Is this the easiest/straight-forward way to do this?

regards,
Suresh

 

[Suresh Jeevanandam]

I got it:
dict([k.split('=') for k in s.split(',')])

regards,
Suresh

 

[Steve Holden]

I got it:
dict([k.split('=') for k in s.split(',')])

Given a string
s = 'a=1,b=2'

I want to create a dictionary {'a': '1', 'b': '2'}

I did,

dict(map(lambda k: k.split('='), s.split(',')))

Is it possible to get rid of the lambda here, without having to define
another function just for this.

Is this the easiest/straight-forward way to do this?

In Python 2.4 you don't even need to construct the list, you can just
use a generator expression instead:

dict(k.split('=') for k in s.split(','))

regards
Steve