Nested blocks

[Josselin]

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

places = [ {:search => adresse}]

geocodes.each { | geocode |
places.collect { | place |
place[:address] = geocode[:address]
place[:latitude] = geocode[:latitude]
place[:longitude] = geocode[:longitude]
}
}

geocodes.nitems => 3

geocodes[0]
=> #<struct Ym4r::GmPlugin::Geocoding:lacemark address="Rue
Caulaincourt, 75018 18ème Arrondissement, Paris, France",
country_code="FR", administrative_area="Ile-de-France",
sub_administrative_area="Paris", locality="Paris",
dependent_locality="18ème Arrondissement", thoroughfare="Rue
Caulaincourt", postal_code="75018", longitude=2.333944,
latitude=48.888226

geocodes[1]
=> #<struct Ym4r::GmPlugin::Geocoding:lacemark address="Lamarck -
Caulaincourt, France", country_code="FR",
administrative_area="Ile-de-France", sub_administrative_area="Paris",
locality="Paris", dependent_locality="18ème Arrondissement",
thoroughfare="Rue Caulaincourt", postal_code="75018",
longitude=2.333944, latitude=48.888226>

geocodes[2]
=> #<struct Ym4r::GmPlugin::Geocoding:lacemark address="Square
Caulaincourt, 75018 18ème Arrondissement, Paris, France",
country_code="FR", administrative_area="Ile-de-France",
sub_administrative_area="Paris", locality="Paris",
dependent_locality="18ème Arrondissement", thoroughfare="Rue
Caulaincourt", postal_code="75018", longitude=2.333944,
latitude=48.888226

places.nitems => 1

places[0]
=> {:longitude=>2.333944, :latitude=>48.888226,
:search=>"caulaincourt,75018, france", :address=>"Square Caulaincourt,
75018 18ème Arrondissement, Paris, France"}

 

[hemant]

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

places = [ {:search => adresse}]

geocodes.each { | geocode |
places.collect { | place |
place[:address] = geocode[:address]
place[:latitude] = geocode[:latitude]
place[:longitude] = geocode[:longitude]
}
}

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

 

[Robert Klemme]

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

places = [ {:search => adresse}]

geocodes.each { | geocode |
places.collect { | place |
place[:address] = geocode[:address]
place[:latitude] = geocode[:latitude]
place[:longitude] = geocode[:longitude]
}
}

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

No need for collect or collect! at all since he is modifying the
Hash(es) inside places. And since places contains only 1 element it
still does so after the iteration. Josselin, what do you expect to get?

Kind regards

robert

 

[Josselin]

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

places = [ {:search => adresse}]

geocodes.each { | geocode |
places.collect { | place |
place[:address] = geocode[:address]
place[:latitude] = geocode[:latitude]
place[:longitude] = geocode[:longitude]
}
}

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

No need for collect or collect! at all since he is modifying the
Hash(es) inside places. And since places contains only 1 element it
still does so after the iteration. Josselin, what do you expect to get?

Kind regards

robert

Thanks for your comments..

well I expect to get 3 items (one for each geocodes item)
where places[:longitude] = geocodes[:longitude], .....
I know that I could do an iteration (as in C) but I tried to do it
without using an indexation ...

places
=> {:longitude=> geocodes[longitude],
:latitude=>geocodes[longitude], :address=>geocodes[address]}

joss

 

[Robert Klemme]

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

places = [ {:search => adresse}]

geocodes.each { | geocode |
places.collect { | place |
place[:address] = geocode[:address]
place[:latitude] = geocode[:latitude]
place[:longitude] = geocode[:longitude]
}
}

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

No need for collect or collect! at all since he is modifying the
Hash(es) inside places. And since places contains only 1 element it
still does so after the iteration. Josselin, what do you expect to get?

Kind regards

robert

Thanks for your comments..

well I expect to get 3 items (one for each geocodes item)
where places[:longitude] = geocodes[:longitude], .....
I know that I could do an iteration (as in C) but I tried to do it
without using an indexation ...

places
=> {:longitude=> geocodes[longitude],
:latitude=>geocodes[longitude], :address=>geocodes[address]}

joss

result = geocodes.map do |geocode|
{:search => adresse, :address => geocode[:address], ...}
end

robert

 

[Josselin]

On 05.03.2007 16:37, hemant wrote:
I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

places = [ {:search => adresse}]

geocodes.each { | geocode |
places.collect { | place |
place[:address] = geocode[:address]
place[:latitude] = geocode[:latitude]
place[:longitude] = geocode[:longitude]
}
}

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

No need for collect or collect! at all since he is modifying the
Hash(es) inside places. And since places contains only 1 element it
still does so after the iteration. Josselin, what do you expect to get?

Kind regards

robert

Thanks for your comments..

well I expect to get 3 items (one for each geocodes item)
where places[:longitude] = geocodes[:longitude], .....
I know that I could do an iteration (as in C) but I tried to do it
without using an indexation ...

places
=> {:longitude=> geocodes[longitude],
:latitude=>geocodes[longitude], :address=>geocodes[address]}

joss

result = geocodes.map do |geocode|
{:search => adresse, :address => geocode[:address], ...}
end

robert

thanks.. so map and collect give the same result... not easy to
forget iteration model ... so powerful methods w Ruby...

 

[dblack]

Hi --

thanks.. so map and collect give the same result... not easy to forget
iteration model ... so powerful methods w Ruby...

They're actually the same method -- just two names bound to exactly
the same thing.


David

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