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Message: [QUOTE="Tassilo v. Parseval, post: 4741460"] Also sprach Jürgen Exner: Oups, right. :-) I somehow failed to see that the cubicroot is x^(1/3) and not x^(1/2). Well, i would be part of the result anyway (when taking the squareroot of a negative number). If you define the range of your result to be within the real numbers, the smallest input that is allowed is 0. But indeed, finding the first number is even harder for complex numbers since you suddenly have two dimensions to consider. Tassilo [/QUOTE]