No return to the parent function

[Joan Miller]

I've a main function called i.e. *foo()* which has a block of code
that is repetead several times (for the error catching code and error
reporting), but that code has a return to exit of *foo()*

-----------
foo():
...
if self.background:
_log.exception(str(error))
return ReturnCode.ERROR, None
else:
raise NameError(error)

 

[Arnaud Delobelle]

I've a main function called i.e. *foo()* which has a block of code
that is repetead several times (for the error catching code and error
reporting), but that code has a return to exit of *foo()*

-----------
foo():
...
if self.background:
_log.exception(str(error))
return ReturnCode.ERROR, None
else:
raise NameError(error)

-----------

So I would tu put that code block into a separated function (*throw()
*), but the problem is that it returns to the parent function (foo()).
How to solve it?

If I understand correctly, you can simply do this:

def throw(...):
if ...:
...
return ...
else:
raise ...

def foo():
...
return throw(...)

HTH

I.e. if throw returns something, foo returns it as well. If throw
raises an exception, it will go through foo. Is this what you want?

 

[Joan Miller]

If I understand correctly, you can simply do this:

def throw(...):
    if ...:
        ...
        return ...
    else:
        raise ...

def foo():
    ...
    return throw(...)

HTH

I.e. if throw returns something, foo returns it as well.  If throw
raises an exception, it will go through foo.  Is this what you want?

Yes, that is it. It was more simple that I had thinked, thanks!

 

[MRAB]

I've a main function called i.e. *foo()* which has a block of code
that is repetead several times (for the error catching code and error
reporting), but that code has a return to exit of *foo()*

-----------
foo():
...
if self.background:
_log.exception(str(error))
return ReturnCode.ERROR, None
else:
raise NameError(error)

-----------

So I would tu put that code block into a separated function (*throw()
*), but the problem is that it returns to the parent function (foo()).
How to solve it?

Call it in a return statement.