Node selection in XSLT

[FaensenD]

Can someone explain why of the following two alternative ways to select
as specific node the first one doesn't work while the second one does?

Variant I:

<recordToken>
<xsl:value-of select="/Root/Case[Id=./Id]/RecordToken" />
</recordToken>


Variant II:

<xsl:variable name="Id">
<xsl:value-of select="./Id" />
</xsl:variable>

<recordToken>
<xsl:value-of select="/Root/Case[Id=$Id]/RecordToken" />
</recordToken>

In Variant I we always get the value of RecordToken of the first Case
node in the XML document. In Variant II we get the RecordToken of the
Case that has the same Id as the current node.

Thank you

Daniel

 

[Joris Gillis]

Can someone explain why of the following two alternative ways to select
as specific node the first one doesn't work while the second one does?

Variant I:

<recordToken>
<xsl:value-of select="/Root/Case[Id=./Id]/RecordToken" />
</recordToken>

"./foo" is the same as "foo"

Your select is then basically: "/Root/Case[Id=Id]/RecordToken" Doesn't make much sense;-)

Inside a [predicate], the context node changes. But, lukily, you can recall the original context node via the XSLT function 'current()':

"/Root/Case[Id=current()/Id]/RecordToken"

In most situations, '.' and 'current()' are the same, but not inside a predicate.

regards,

 

[Martin Honnen]

Can someone explain why of the following two alternative ways to select
as specific node the first one doesn't work while the second one does?

Variant I:

<recordToken>
<xsl:value-of select="/Root/Case[Id=./Id]/RecordToken" />
</recordToken>

Well this works as defined but probably does not do what you want. I
guess you are looking for
<xsl:value-of select="/Root/Case[Id=current()/Id]/RecordToken" />

See <http://www.w3.org/TR/xslt#function-current>.