numbering variables

[remi]

Hello,

I have got a list like : mylist = ['item 1', 'item 2',....'item n'] and
I would like to store the string 'item1' in a variable called s_1,
'item2' in s_2,...,'item i' in 's_i',... The lenght of mylist is finite ;-)
Any ideas ?
Thanks a lot.
Rémi.

 

[Fredrik Lundh]

I have got a list like : mylist = ['item 1', 'item 2',....'item n'] and I would like to store the
string 'item1' in a variable called s_1, 'item2' in s_2,...,'item i' in 's_i',...

why?

</F>

 

[Patrick Useldinger]

Hello,

I have got a list like : mylist = ['item 1', 'item 2',....'item n'] and
I would like to store the string 'item1' in a variable called s_1,
'item2' in s_2,...,'item i' in 's_i',... The lenght of mylist is finite ;-)
Any ideas ?
Thanks a lot.
Rémi.

Use a dictionary: variable['s_1']= mylist.pop(), variable['s_2'] =
mylist.pop() ...

 

[remi]

Patrick Useldinger a écrit :

Hello,

I have got a list like : mylist = ['item 1', 'item 2',....'item n']
and I would like to store the string 'item1' in a variable called s_1,
'item2' in s_2,...,'item i' in 's_i',... The lenght of mylist is
finite ;-)
Any ideas ?
Thanks a lot.
Rémi.

Use a dictionary: variable['s_1']= mylist.pop(), variable['s_2'] =
mylist.pop() ...

Ok thanks but is there a way to automate this variable numbering ? Such
like :
i = 0
for i <=len(mylist)
s_i=mylist
i = i +1
or as you suggest :
i = 0
while i<=len(mylist)
variable['s_i']=mylist.pop()
i = i+1
Thanks.
Rémi.

 

[remi]

Fredrik Lundh a écrit :

I have got a list like : mylist = ['item 1', 'item 2',....'item n'] and I would like to store the
string 'item1' in a variable called s_1, 'item2' in s_2,...,'item i' in 's_i',...

why?

I want to convert a very simple *.tex file into a very simple *.xml file
mylist is made by :

file_in = open('in.tex','r')
file_string = file_in.read()

corps = r"""\\begin{document}(?P<contents>.*)\\end{document}"""
compile_obj = re.compile(corps, re.IGNORECASE| re.DOTALL)
match_obj = compile_obj.search(file_string)
contents = match_obj.group('contents')

sect = r'\\section{(.*)}'
motif1 = re.compile(sect)
mylist = re.split(motif1,contents)

I want to store each item of mylist in a variable (and after "xmlize" it
little by little). The lengh of mylist isn't fixed it depends on the
*.tex file.
Thanks.
Rémi.

 

[Fredrik Lundh]

i = 0
while i<=len(mylist)
variable['s_i']=mylist.pop()
i = i+1

variable['s_' + str(i)]=mylist.pop()

but that while and pop stuff is pretty weird; maybe you should read the
sections on lists, for loops, and string formatting in the Python tutorial?

here's a shorter way to create that dictionary:

variable = {}
for item in mylist:
variable["s_%d" % len(variable)] = item

and here's the obligatory one-liner:

variable = dict(("s_" + str(k), v) for k, v in enumerate(mylist))

(shorter, but not exactly clearer, especially not if you're new to Python)

</F>

 

[Fredrik Lundh]

I want to store each item of mylist in a variable (and after "xmlize" it little by little).

why not just process the items in the list?

for item in mylist:
print tex2xml(item)

</F>

 

[remi]

Fredrik Lundh a écrit :

why not just process the items in the list?

That's right.

for item in mylist:
print tex2xml(item)

where tex2xml() is the main converting function i guess.
So i should change "print tex2xml(item)" to a kind of
"output.write(tex2xml(item))".

Ok, i try this too but i think it will lead to a "line by line"
processing of the file... I try.
Thanks.
Rémi.

 

[remi]

Fredrik Lundh a écrit :

variable['s_i']=mylist.pop()

variable['s_' + str(i)]=mylist.pop()

but that while and pop stuff is pretty weird;

Why ? Because it destroys the list ?

maybe you should read the
sections on lists, for loops, and string formatting in the Python tutorial?

here's a shorter way to create that dictionary:

variable = {}
for item in mylist:
variable["s_%d" % len(variable)] = item

maybe a dictionnary is more easely usable and reusable than a list...
Thanks a lot for your help.

and here's the obligatory one-liner:

variable = dict(("s_" + str(k), v) for k, v in enumerate(mylist))

(shorter, but not exactly clearer, especially not if you're new to Python)

As a beginner, I agree at 100% even if the latter is nicer !
Rémi.
I send to people form clp a little sun from Toulouse (France)

 

[Ron_Adam]

Hello,

I have got a list like : mylist = ['item 1', 'item 2',....'item n'] and
I would like to store the string 'item1' in a variable called s_1,
'item2' in s_2,...,'item i' in 's_i',... The lenght of mylist is finite ;-)
Any ideas ?
Thanks a lot.
Rémi.

Why not just access the list by index? Just start with zero instead
of 1.

mylist = ['item 1', 'item 2',....'item n']


mylist[0] is 'item 1'
mylist[1] is 'item 2'
..
..
mylist[n-1] is 'item n'


Ron Adam

 

[Steve]

Hello,

I have got a list like : mylist = ['item 1', 'item 2',....'item n'] and
I would like to store the string 'item1' in a variable called s_1,
'item2' in s_2,...,'item i' in 's_i',... The lenght of mylist is finite ;-)
Any ideas ?
Thanks a lot.
Rémi.

Why not just access the list by index? Just start with zero instead
of 1.

If you _really_ must have one-based indexes, use a
sentinal at the beginning of the list:

>>> mylist = ['item 1', 'item 2',....'item n']
>>> s = [None] + mylist # the sentinal is never used
>>> print s[1] 'item 1'
>>> print s[28] 'item 28'
>>> print s[29] # there are only 28 items!

Traceback (most recent call last):
File "<stdin>", line 1, in ?
IndexError: list index out of range


Then you can process all the items without needing to
remember how many there are:
.... do_something(s)